1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Darina [25.2K]
3 years ago
10

What is 3Y + -6 + 7Y + 4Y

Mathematics
1 answer:
Rudik [331]3 years ago
7 0
So first find like terms. The like terms are 3y 7y and 4y. Now add all of them together to get 14y and then just put the -6 back in the equation for your final answer. Final answer: 14y - 6
You might be interested in
Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
3 years ago
An equation parallel and perpendicular to 4x+5y=19
mestny [16]

Answer:

An equation parallel to 4x + 5y = 19 would be y = -4/5x +12.

An equation perpendicular to 4x + 5y = 19 would be y = 5/4x + 10.

Step-by-step explanation:

The equation given represents a linear equation in Standard Form (Ax + By = C).  Lines that are parallel to each other go the same direction and don't touch, so their slopes must be the same.  However, lines that are perpendicular go in opposite directions and intersect, so their slopes must be the direct opposite of each other.  In order to find the slope, you must first convert from the Standard Form given to Slope Intercept Form (y = mx +b).  When you solve the given equation for 'y', you get: y = -4/5x + 19, where the slope = -4/5.  To make a parallel equation, simply keep the same slope and choose a different y-intercept ('b').  To make a perpendicular equation, take the direct opposide of your slope 5/4 (positive) and choose a different y-intercept.  

8 0
3 years ago
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
3 years ago
The rectangle shown has a perimeter of 154 cm and the given area. Its length is 5 more than five times its width. Write and solv
Andreyy89

Answer:

2(L+W) = 34

L + W = 17

.

L*W = 52

.

L = 2W+5

.

2L + 2W = 34

L - 2W = 5

--------------- add

3L = 39

L = 13

8 0
3 years ago
Read 2 more answers
Tim earned $300 in five days. After the first day, he earned $10 more each day than the day before. How much did Tim earn on the
Vika [28.1K]
Use the equation 300⇒5x to find how much tim made each day on average. 
x⇒60   so, Day 1: $60, Day 2: $70 etc.. so the equation 300=5x+10 suffices the problem. 300⇒5x+10 ⇒    290=5x
x=58
So, Tim earned $58 his first day. Hope this helped.
8 0
3 years ago
Read 2 more answers
Other questions:
  • -2x3x simplify please
    5·1 answer
  • mr burns class is taking a field trip to the planetarium. The trip will cost $27 for each student. There are 18 students in his
    14·2 answers
  • In the data set {16, 17, 18, 19, 20, 22, 24, 27, 29} how do you find<br> the 2nd quartile
    13·1 answer
  • The Foot Locker is having a 60% off sale on shorts. John paid $18 for a pair of shorts. What was the original price of the short
    9·1 answer
  • Explain how you can solve 8x8 if you know how to multiply with 4 but not how to multiply with 8
    12·2 answers
  • What percent of 80 is 20​
    8·1 answer
  • Plz help I have a time test
    7·1 answer
  • Researchers surveyed 250 college students at one time. They were asked if they were taking any engineering classes and whether o
    12·1 answer
  • The angle marked a = 75°.<br> Work out the value of x.<br><br> The diagram is not drawn accurately.
    13·1 answer
  • Pls help me with this question
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!