So hmmm notice the picture below
thus
solve for "h"
Answer:
y = 0.6x – 4
or
y =
3/5x
-4
Step-by-step explanation:
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
b.7
Step-by-step explanation:
you take the three and substitute that in for x. 2(3) + 1
2(3)=6 then add 1
Answer:
6x - 9
3(2x−3)
2a(5b+3)
Step-by-step explanation:
Factor 6a+10ab
10ab+6a
Factor 6x−9
6x−9
=3(2x−3)
:))
