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Svetradugi [14.3K]
3 years ago
9

How a strontium salt emits colored light​

Chemistry
1 answer:
Bond [772]3 years ago
3 0

Answer:

When excited electrons fall to lower energy levels, they can release energy in the form of light. metal ions in the salts used in the flame tests.

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The Scott Test is used when which drug is suspected?
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It is a presumptive test for cocaine.
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What are the branches of chemistry and their definition?
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The five main branches of chemistry are organic chemistry, inorganic chemistry, analytical chemistry, physical chemistry and biochemistry. Chemistry can be further divided into many sub-branches that may fall under more than one of the main branches.
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What are some problems chemist must consider when developing new technologies?
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Materials Science is the study of solid stuff.<br>A True<br>B) False​
miv72 [106K]

Answer:

true

Explanation:

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and we all know matter involve solid liquid or gas

7 0
3 years ago
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In a certain city, electricity costs $0.15 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.00 hours
Vanyuwa [196]

(a) Power of bulb is 100 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{100}{1000}kW=0.1 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.1 kW\times 2190 h=219 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

Cost=\$ (219\times 0.15)=\$ 32.85

Therefore, annual cost of incandescent light bulb is \$ 32.85

(b) Power of bulb is 25 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{25}{1000}kW=0.025 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.025 kW\times 2190 h=54.75 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

Cost=\$ (54.75\times 0.15)=\$ 8.21

Therefore, annual cost of fluorescent bulb is \$ 8.21.

7 0
3 years ago
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