Answer:
The molar mass of the vapor is 43.83 g/mol
Explanation:
Given volume of gas = V = 247.3 mL = 0.2473 L
Temperature = T = 100
= 373 K
Pressure of the gas = P = 745 mmHg (1 atm = 760 mmHg)

Mass of vapor = 0.347 g
Assuming molar mass of gas to be M g/mol
The ideal gas equation is shown below

The molar mass of the vapor comes out to be 43.834 g/mol
Hubris: excessive pride or self-confidence.
Answer: 0.16 moles
Explanation: According to Avogadro's law, 1 mole of every gas at STP occupies a volume of 22.4 Liters.
Given: Volume occupied = 3.55 L
From Avogadro's law,
22.4 L of
corresponds to= 1 mole
3.55 L of
correspond to=
Hi, I am an AP chemistry student so I am confident this answer is correct. The answer would be 3.38 L or 3380 mL