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3 years ago

The Scott Test is used when which drug is suspected?

Chemistry

2 answers:

hoa [83]3 years ago

8 0

Answer:

Cocaine

Explanation:

The Scott test is a presumptive, qualitative colorimetric test for the presence of cocaine that is carried out in the laboratory or on the field. It consists of 3 steps;

Suspected substance is mixed with cobalt thiocyanate in an aqueous/glycerin solution.
Acidification of the resulting solution using HCl.
Extraction of substance's precipitate using chloroform

Blue organic phase indicates the presence of cocaine in substance while colourless organic phase indicates the absence.

marishachu [46]3 years ago

4 0

It is a presumptive test for cocaine.

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3 years ago

the student records the concentration of the stock solution of H2O2 to be 0.950 M. The student proceeds to prepare the reaction

lana [24]

Answer:

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Explanation:

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3 years ago

Which of the following are not single-displacement reactions?

Goshia [24]

Answer:

$\boxed{\text{B and C }}$

Explanation:

In a single-displacement reaction, one element exchanges partners with another element in a compound.

$\textbf{A. } \rm Fe + 2HCl \longrightarrow FeCl_2 + H_2$

This is a single-displacement reaction, because the element Fe exchanges partners with H in HCl.

$\textbf{B. } \rm KOH + HNO_3 \longrightarrow H_2O + KNO_3$

This is not a single-displacement reaction, because it is a reaction between two compounds.

This is a double displacement reaction in which the K⁺ and H⁺ cations change partners with the anions.

$\textbf{C. } \rm Na_2S + 2HCl \longrightarrow 2NaCl + H_2S$

This is not a single-displacement reaction. It is another double displacement reaction, in which the Na⁺ and H⁺ cations change partners with the anions.

$\textbf{D. } \rm Ca + 2HOH \longrightarrow Ca(OH)_2 + H_2$

This is a single-displacement reaction, because the element Ca exchanges partners with H in H₂O.

$\boxed{\textbf{B and C }}$ are not single-displacement reactions.

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