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vodomira [7]
3 years ago
9

The Scott Test is used when which drug is suspected?

Chemistry
2 answers:
hoa [83]3 years ago
8 0

Answer:

Cocaine

Explanation:

The Scott test is a presumptive, qualitative colorimetric test for the presence of cocaine that is carried out in the laboratory or on the field. It consists of 3 steps;

  • Suspected substance is mixed with cobalt thiocyanate in an aqueous/glycerin solution.
  • Acidification of the resulting solution using HCl.
  • Extraction of substance's precipitate using chloroform

<em>Blue organic phase indicates the presence of cocaine in substance while colourless organic phase indicates the absence.</em>

marishachu [46]3 years ago
4 0
It is a presumptive test for cocaine.
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PSYCHO15rus [73]

Answer:

Schaus Swallowtail Butterfly

Explanation:

They eat food plants, torchwood and wild lime. And their an endangered species in Florida.

3 0
2 years ago
Give the product of the reaction of excess benzene (2 equivalents) with dichloromethane and alcl3.
SOVA2 [1]
Hello!

The product of the reaction of excess benzene with dichloromethane is diphenylmethane. 

The reaction that benzene undergoes with dichloromethane is a Friedel-Crafts Alkylation, in which firstly Benzene is alkylated to Benzyl Chloride, and after that, the Benzyl Chloride reacts with another equivalent of Benzene to form the compound Diphenylmethane. The Reaction Scheme is shown in the image below:

Have a nice day!

5 0
3 years ago
CH2OHCH2OH is a general example of: an ethyl alcohol a methyl alcohol a polyhydroxyl alcohol an organic acid
RoseWind [281]

CH2OHCH2OH is a general example of a polyhydroxyl alcohol. A polyhydroxyl alchol is one in which there are two hydroxyl groups present in the substance. The –OH group attached to both the carbon atoms.

4 0
3 years ago
Read 2 more answers
What is the Net Ionic equation for this chemical reaction: FeBr2+Na2S=FeS+2NaBr​
Artyom0805 [142]

Answer: Fe<em>(aq)</em>+S<em>(aq)</em>=FeS<em>(s)</em>

Explanation: The Sodium and Bromine are spectator ions because they don't react with anything, you can see this by writing the ionic equation like so:

1.) Molecular formula (given): FeBr2 (aq)+Na2S (aq)= FeS(s)+2NaBr(aq)

Each dissolved FeBr2 breaks up into one Fe with a charge of 2+ and two Br with a negative charge. This gives you:

Fe(aq)+ 2Br(aq)+Na2S(aq)=FeS(s)+2NaBr

2.) Now repeat what was shown with the other compounds in the given molecular formula, and pay attention to the states that each ion is in (solid, liquid, aqueous, gas) because this will give you the ionic equation, which from there you can get rid of any ions that don't change amount or state.

3.) Ionic formula: Fe(aq)+ <u>2Br(aq)</u>+<u>2 Na(aq)</u>+S (aq)=FeS(s)+<u>2 Na(aq)+2Br(aq)</u>

4.)When you've derived a total ionic equation (above), you'll  find that some ions appear on both sides of the equation in equal numbers. For example, in this case two Na cations and two Br anions appear on both sides of the total ionic equation. What does this mean? It means these ions don't participate in the chemical reaction. They're present before and after the reaction. Nothing happens to them. So those are removed and you're left with the net ionic: Fe(aq)+S(aq)=FeS(s)

Hope this helps :)

7 0
2 years ago
1. Mg + N2 —&gt; MgN2
quester [9]

(1) IS THE BALANCED EQUATION AND REACTANT-> MG AND N2 AND PRODUCT ->MGN2.

(2) IS NOT BALANCED AND REACTANT->CF4 AND BR AND PRODUCT IS CBR4 AND F2

8 0
3 years ago
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