Answer:
(a) 7.5 seconds
(b) The horizontal distance the package travel during its descent is 1737.8 ft
Step-by-step explanation:
(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀
The initial height of the object s₀ = 900 feet
The initial vertical velocity of the object v₀
= 0 m/s
The time it takes the package to strike the ground is found as follows;
0 = -16·t² + 0×t + 900
900 = 16·t²
t² = 900/16 = 62.25
t = √62.25 = 7.5 seconds
(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have
158 miles/hour = 231.7126 ft/s
The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place
The horizontal distance the package travel during its descent = 1737.8 ft.
Answer:
B
Step-by-step explanation:
You can see from the sequence 26, 44, 62, 80,.... that each term after the first is 18 larger than the previous term.
<u>The first 4 seconds' distance is given</u>, so
- 5th second distance is 80+18=98
- 6th second distance is 98+18=116
- 7th second distance is 116+18=134
To find total distance for 7 seconds, we add up all the individual distances:
26+44+62+80+98+116+134=560
Answer choice B is right.
21 + p = 44
Subtract 21 from both sides;
21 + p - 21 = 44 - 21
p = 23
Answer:
L = 1.80 dollar/pound
H = 2.60 dollar/pound
T = 2.04 dollar/pound
Step-by-step explanation:
u = How much pounds of the L candy, unknown
V = 3 pounds, the H candy
Ok so to find this we need to find 25% of 8 and then add that number to 8 itself. SO .25*8=2. So 2+8=10. So the answer is 10. IF you don't get it just ask and i can try to re explain