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2 years ago

* PLEASE HELP* 1. What does 4x + 10x = and 2.Which expression is an example of having like-terms?

Mathematics

2 answers:

NARA [144]2 years ago

6 0

4x + 10x = 14x
And 5x + 3x is an example of having like terms.

jok3333 [9.3K]2 years ago

5 0

Answer:

1. 14x

2. 5x + 3x

Step-by-step explanation:

1) 4x + 10x = 14x

2) By "like-terms" the question means that the expression contains the same variable part. Therefore, the only expression that meets that is 5x + 3x.

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What is the function? F(x)=2x^2-3x+1

olasank [31]

Answer:

To satisfy the hypotheses of the Mean Value Theorem a function must be continuous in the closed interval and differentiable in the open interval.

Step-by-step explanation:

As f(x)=2x3−3x+1 is a polynomial, it is continuous and has continuous derivatives of all orders for all real x, so it certainly satisfies the hypotheses of the theorem.

To find the value of c, calculate the derivative of f(x) and state the equality of the Mean Value Theorem:

dfdx=4x−3

f(b)−f(a)b−a=f'(c)

f(x)x=0=1

f(x)x=2=3

Hence:

3−12=4c−3

and c=1.

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2 years ago

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Which of the following expressions is equivalent to the expression 36 + 42?

olga2289 [7]

The answer is 6(6 + 7)

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Plz help, I'm taking an Advanced class (Algebra) Will give brainliest ✔✔✔✔✔✔✔✔✔

bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$(x_1, y_1)$ and $(x_2, y_2)$ are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

$h(0) = 3(5)^0 = 3 \cdot 1 = 3$

$h(1) = 3(5)^1 = 3 \cdot 5 = 15$

$h(2) = 3(5)^2 = 3 \cdot 25 = 75$

$h(3) = 3(5)^3 = 3 \cdot 125 = 375$

Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

$m = \dfrac{15 - 3}{1 - 0} = \boxed{12}$

<u>Section B</u>

$m = \dfrac{375 - 75}{3 - 2} = \boxed{300}$

Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

$\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25$

It is 25 times greater. This is because $3(5)^x$ is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.