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Nesterboy [21]
3 years ago
11

Help I need help please help I need help

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer: 2 ribbons can be cut

Since 3/4 divided by 1/3 = 2.25, therefore you can make 2 full sized ribbons. He will have 3/4 of a ribbon left.

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Which of the following is an example of direct variation?
Dafna11 [192]

Answer: Choice A) y = cx

The 'c' is the constant of variation

For example, if c = 2, then y = 2x is a direct variation. Whatever x is, we double it to get y. As x increases, so does y. As x decreases, then so does y. Both x and y increase/decrease together.

Direct variation equations always go through the origin, and they are always linear. The 'c' plays the role of the slope. You can think of y = cx as y = mx+b where b = 0 in this case and c = m.

3 0
3 years ago
Please help if you want brianleits pleaee :( ni links please​
Katyanochek1 [597]
A is the answer i believe
3 0
3 years ago
What equation do I need to use?
goldenfox [79]
To ease your problem, consider "L" as you x-axis
Then the coordinate become:
A(- 4 , 3)   and B(1 , 2) [you notice that just the y's changed]

This is a reflection problem.
Reflect point B across the river line "L" to get B', symmetric of B about L.
The coordinates of B'(1 , -1) [remember L is our new x-axis]
JOIN A to B' . AB' intersect L, say in H
We have to find the shortest way such  that AH + HB = shortest.
But HB = HB' (symmetry about L) , then I can write instead of 
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6 0
4 years ago
Question 1 (2 points) The total distance in centimeters a toy robot moves varies directly with the time in seconds. The toy robo
makvit [3.9K]

Answer:

a.    T = 17s

b.    D = 72cm

Step-by-step explanation:

Given

<em>Direct Variation</em>

Distance(D)\ \alpha\ Time (T)

D = 264 cm when T = 11 s

Calculating (a)

First, the constant of variation (k) as to be calculated;

Since, there exist a direct proportion; then,

D\ \alpha\ T

D = kT

Make k the subject of formula

k = \frac{D}{T}

<em>D = 264 cm when T = 11 s; So</em>

<em />k = \frac{264}{11}<em />

<em />k = 24<em />

So: Solving for (a)

D = 408

Substitute 408 for D and 24 for k in D = kT

408 = 24 * T

Divide both sides by 24

\frac{408}{24} = T

T = \frac{408}{24}

T = 17s

<em>Hence, time to move a distance of 408cm is 17s</em>

Calculating (b)

T = 3

Substitute 3 for T and 24 for k in D = kT

D = 24 * 3

D = 72cm

<em>Hence, distance covered in 3 seconds is 72cm</em>

4 0
4 years ago
15+6X = Y(32+ 12x)-|
hammer [34]

i hope it helps please mark me as brainliest please

6 0
3 years ago
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