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Zinaida [17]
4 years ago
8

fashion for All has jeans on sale for $13. designer pants has jeans on sale for $26. write the total costs of 1,2,3, and 4 pairs

of jeans for each store. then compare the total cost of 4 pairs of jeans.
Mathematics
1 answer:
cestrela7 [59]4 years ago
4 0
Total cost of 1, 2, 3, 4 pairs of jeans per store:

Fashion For All:
13 x 1 = 13
13 x 2 = 26
13 x 3 = 39
13 x 4 = 52

Designer Pants:
26 x 1 = 26
26 x 2 = 52
26 x 3 = 78
26 x 4 = 104


COMPARISON:
Designer Pants = $104, Fashion For All = $52
<em>Compare:
1. we can say that 4 pairs of jeans from designer Pants cost </em><em>52 $ more that 4 pairs of jeans from Fashion For All
2. We can say that the price is twice as high in Designer Pants than in Fashion For All
</em>HOPE IT HELPED!<em>
</em><em />
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19) Albert says that the two systems of equations shown have the same solutions.
k0ka [10]

Answer:

option A) Agree, because the solutions are the same is correct.

Step-by-step explanation:

FIRST SYSTEM

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solving the system

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\mathrm{Multiply\:}-x-y=-3\mathrm{\:by\:}6\:\mathrm{:}\:\quad \:-6x-6y=-18

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adding the equation

-6x-6y=-18

+

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so the system becomes

\begin{bmatrix}6x+y=2\\ -5y=-16\end{bmatrix}

solve -5y for y

-5y=-16

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simplify

y=\frac{16}{5}

\mathrm{For\:}6x+y=2\mathrm{\:plug\:in\:}y=\frac{16}{5}

6x+\frac{16}{5}=2

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6x+\frac{16}{5}-\frac{16}{5}=2-\frac{16}{5}

6x=-\frac{6}{5}

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x=-\frac{1}{5}

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x=-\frac{1}{5},\:y=\frac{16}{5}

SECOND SYSTEM

2x-3y = -10

-x-y=-3

solving the system

\begin{bmatrix}2x-3y=-10\\ -x-y=-3\end{bmatrix}

\mathrm{Multiply\:}-x-y=-3\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y=-6

\begin{bmatrix}2x-3y=-10\\ -2x-2y=-6\end{bmatrix}

-2x-2y=-6

+

\underline{2x-3y=-10}

-5y=-16

so the system of equations becomes

\begin{bmatrix}2x-3y=-10\\ -5y=-16\end{bmatrix}

solve -5y for y

-5y=-16

Divide both sides by -5

\frac{-5y}{-5}=\frac{-16}{-5}

Simplify

y=\frac{16}{5}

\mathrm{For\:}2x-3y=-10\mathrm{\:plug\:in\:}y=\frac{16}{5}

2x-3\cdot \frac{16}{5}=-10

2x=-\frac{2}{5}

Divide both sides by 2

\frac{2x}{2}=\frac{-\frac{2}{5}}{2}

Simplify

x=-\frac{1}{5}

Therefore, the solution to the SECOND SYSTEM is:

x=-\frac{1}{5},\:y=\frac{16}{5}

Conclusion:

As both systems of equations have the same solution.

Therefore, we conclude that Albert is right when says that the two systems of equations shown have the same solutions.

Hence, option A) Agree, because the solutions are the same is correct.

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