Answer:
It would be in the $3.30 or lower zone
Step-by-step explanation:
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
91
Step-by-step explanation:
I used a calculator and if you add 76, 93, 89, 71 to 91 it equals 420 and if you divide that by 5 it is 84.
Hope this helps!
its a. numerical expression.
Answer:
$9 I think
Step-by-step explanation:
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