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2 years ago

Divide p(x)=x^4+6x^3+7x^2-6x-8 by x+4. What is the remainder

Mathematics

1 answer:

postnew [5]2 years ago

3 0

Use the remainder theorem; dividing a polynomial $p(x)$ by $x-c$ leaves a remainder equal to $p(c)$ . Here

$p(x)=x^4+6x^3+7x^2-6x-8$

$\implies p(c)=(-4)^4+6(-4)^3+7(-4)^2-6(-4)-8=\boxed{0}$

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Step-by-step explanation: hope this helped :)

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