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3 years ago

Divide p(x)=x^4+6x^3+7x^2-6x-8 by x+4. What is the remainder

Mathematics

1 answer:

postnew [5]3 years ago

3 0

Use the remainder theorem; dividing a polynomial $p(x)$ by $x-c$ leaves a remainder equal to $p(c)$ . Here

$p(x)=x^4+6x^3+7x^2-6x-8$

$\implies p(c)=(-4)^4+6(-4)^3+7(-4)^2-6(-4)-8=\boxed{0}$

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A path of 0.5 meter wide runs round within a square garden of side 15 m.Find it's perimeter ?<br>

azamat

Answer:

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Step-by-step explanation:

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2 years ago

Select all the points that are on the graph of the line LaTeX: 2x + 4y = 202 x + 4 y = 20.

liraira [26]

Answer:

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Step-by-step explanation:

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3 years ago

A rectangular table is 5 1/4 feet by 3 3/4 feet. What is the area of the table?

enot [183]

Answer:

19 11/16 or 315/16

Steps:

Turn the fractions into an improper fraction and then multiply straight across

5 1/4 = 21/4

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(21/4)*(15/4)= 315/16= 19 11/16

Yes you got it right :)

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3 years ago

Read 2 more answers

The walls of a room are representations of what basic element of geometry? A. point B. line C. plane D. ray

kkurt [141]

In geometry,

A point represents a point

Two points define a line extended on both sides of the points.

Two points define a ray if it extends on only one side of either of the points.

Three or more than three points define a plane.

Now as far as a wall is considered, it is a flat surface on which we can plot infinite points.

Hence the wall represents a plane.

Option C) is the right answer.

6 0

3 years ago

Read 2 more answers

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

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3 years ago