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Bad White [126]
3 years ago
5

Determine the total numbers of zero f(x) = 23 – 3x2 – 2x + 6

Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

f(x) = 29

Step-by-step explanation:

f(x)=23-(3x0)-(2X0)+6

f(x)=23+6

f(x)=29

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5q greater than or equal to 8q -3/2
kakasveta [241]

5q ≥ 8q - 3/2

<em><u>Add 3/2 to both sides.</u></em>

3/2 + 5q ≥ 8q

<em><u>Subtract 5q from both sides.</u></em>

3/2 ≥ 3q

<em><u>Multiply both sides by 2.</u></em>

3 ≥ 6q

<em><u>Divide both sides by 6.</u></em>

0.5 ≥ q.

The value of q is less than or equal to 0.5.

8 0
3 years ago
Bilal's fishing line was on a spool with a radius of 4cm. Suddenly, a fish pulled on the line, and the spool spun 16 times befor
Aleks [24]

First, I'd like to say that this question is flawed because the diameter of the spool changes as you pull the line out. Some would argue it's negligible I suppose.

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circumference = 2*pi*r = 2 * pi * 4cm = about 25.133 cm

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16 * (25.133 cm)

= 402.128 cm

8 0
3 years ago
Read 2 more answers
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8 0
3 years ago
I don't understand the substitution method?
liq [111]
It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.

In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x

2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y

now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
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-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5

now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0

and now we have solved the problem. x=0 and y=-5

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3 years ago
Grace loves to eat salad how many salads can she put together if she can choose one from each of the following: two types of let
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# of salads possible = 2*4*7 = 56.
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