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3 years ago

In how many different ways can all the letters of the word zookeeper be arranged?

Mathematics

2 answers:

vampirchik [111]3 years ago

6 0

An infinite amount seeing as you can have infinite of each number

s344n2d4d5 [400]3 years ago

3 0

The 9! ways of arranging the letters in ZOOKEEPER have to be divided by 2! and 3! the reason being that having fixed the positions of the non-repeated letters, the O's may be arranged in 2! ways and the E's in 3! ways without making a different word:
$\frac{9!}{2!3!}=30240$
The answer is: 30,240 ways.

You might be interested in

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

Six years after a tree was planted, its height was 7 feet. Nine years after it was planted, its height was 16 feet. Which of the

pychu [463]

Considering that the grows at a constant rate we can form an equation where x = how many years after it was planted
and y = its height

Now we just need to find how many feet it grows each year. To do that we just need to compare its height from a certain age to another:
6 years after it was planted : 7 feet,
so x=6 and y = 7

9 years after it was planted: 16 feet
so x= 9 y=16

With thay we can conclude that in 3 years , the tree grew 9 feet. To discover how much the tree grow each year we just nee to divide 9 feet by 3 years which is 3 feet every year.

To write the equatopn now we just need to find the y-intercept which we can discover by setting x to 0:
If in 6 years after the tree was planted it is 7 feet long , we can discover how long it was when it was planted by subtracting 6 years of growth (The slope ) which is 3
7 - 6(years)×3(feet the tree grow each year)
7 - 18 = -11
The tree was -11 feet long when it was planted
which is our y-intercept
( I know it doesnt make sense , but if you apply to a graph it will make more sense )

Now we can make the equation
y = 3x -11

7 0

3 years ago

a post is driven into the ground. the first strike drives the post 30 inches into the ground. The next strikes drives the post 2

nevsk [136]

Your answer should be 156 inches

3 0

3 years ago

Read 2 more answers

What is the fewest number of expressions that a equation can contain?

nlexa [21]

The fewest number of expressions is 3.

8 0