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Triss [41]
3 years ago
5

Which expressions are equivalent to 10a - 25 + 5b

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:

<h2>(2a − 5 + b) · 5</h2><h2>10×(a − 2.5 + 0.5b)</h2><h2>(−2a + 5 − b) ⋅ (−5)</h2>

Step-by-step explanation:

10a-25+5b\\\\-2(-5a-25+5b)=(-2)(-5a)+(-2)(-25)+(-2)(5b)\\=10a+50-10b\qquad NOT\\\\(2a-5+b)(5)=(2a)(5)+(-5)(5)+(b)(5)=10a-25+5b\qquad YES\\\\10(a-2.5+0.5b)=(10)(a)+(10)(-2.5)+(10)(0.5b)\\=10a-25+5b\qquad YES\\\\(-2a+5-b)(-5)=(-2a)(-5)+(5)(-5)+(-b)(-5)\\=10a-25+5b\qquad YES\\\\-10(-a-2.5-0.5b)=(-10)(-a)+(-10)(-2.5)+(-10)(-0.5b)\\=10a+25+5b\qquad NOT

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3 0
3 years ago
Read 2 more answers
The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2
Darina [25.2K]

Answer:

a) The estimates for the solutions of 4\cdot x^{2}-4\cdot x -1 = 0 are x_{1}\approx -0.25 and x_{2} \approx 1.25.

b) The estimates for the solutions of 4\cdot x^{2}-4\cdot x -1 = 2 are x_{1}\approx -0.5 and x_{2} \approx 1.5

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial y = 4\cdot x^{2}-4\cdot x -1, where x is related to the horizontal axis of the Cartesian plane, whereas y is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) 4\cdot x^{2}-4\cdot x -1 = 0

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

x_{1}\approx -0.25, x_{2} \approx 1.25

b) 4\cdot x^{2}-4\cdot x -1 = 2

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

x_{1}\approx -0.5, x_{2} \approx 1.5

5 0
3 years ago
Find the mean, median, mode, and range of the data 10, 13, 7, 6, 9, 4, 6, 3, 5​
elena-s [515]
Median is 6 range is 9 mode is 6 and mean is 7
7 0
2 years ago
1) At a diner, the cost for a specialty waffle and a hashbrown is $9.50. The cost for 2 specialty
klemol [59]

9514 1404 393

Answer:

  • waffle $8
  • hashbrowns $1.50

Step-by-step explanation:

Using w and h for the costs of a waffle and hashbrowns, respectively, we can write the equations for the purchase amounts as ...

  w + h = 9.50

  2w + 3h = 20.50

Subtracting twice the first equation from the second gives ...

  (2w +3h) -2(w +h) = (20.50) -2(9.50)

  h = 1.50 . . . . . . simplify

  w = 9.50 -h = 8.00 . . . . . find w using the first equation

The cost of a waffle is $8.00; the cost of hashbrowns is $1.50.

4 0
3 years ago
#2 is the one I need help with
sleet_krkn [62]

Step-by-step explanation:

By arc sum Postulate of a circle:

2 x + 3x + 4x = 360°

9x = 360°

x = 360°/9

x = 40°

3x = 3* 40° = 120°

By inscribed angle theorem:

m\angle 1= \frac {1}{2} \times 3x\\\\\therefore m\angle 1= \frac {1}{2} \times 120°\\\\\huge \red {\boxed {\therefore m\angle 1= 60°}}

By tangent secant theorem:

m\angle 2 = \frac {1}{2} \times 3x\\\\\therefore m\angle 2 = \frac {1}{2} \times 120°\\\\\huge \purple {\boxed {\therefore m\angle 2 = 60°}}

Since, measure of central angle is equal to the measure of its corresponding minor arc.

m\angle 3 = 3x\\\\\huge \pink {\boxed {\therefore m\angle 3 = 120°}}

By angle sum Postulate of a triangle:

m\angle 3 + 2 m\angle 4 = 180°\\\\120° + 2 m\angle 4 = 180° \\\\2 m\angle 4 = 180°- 120° \\\\2 m\angle 4 = 60° \\\\m\angle 4 = \frac {60°}{2} \\\\\huge \orange {\boxed {m\angle 4 =30°}}

3 0
3 years ago
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