The probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
Given a fair dice and tossing a fair coin sixteen times.
We have to find the probability that the total number of heads in all the coin tosses equals 12.
The probability lies between 0 and 1.
Probabiltiy of coming head when the coin is tossed 1 time is 0.5 and probability of coming tails is also 0.5.
Let X shows the sum of heads while tossing.
P(X=12)=?
We can find the probability using binomial theorem.
=
We have to toss sixteen times and out of 16 times we need head 12 times.
=16!/12!4!*0.00024*0.0625
=1820*0.000015
=0.0273
Hence the probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
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Answer:
-5
Step-by-step explanation:
4x-3 = 7x+12
- Subtract 12 from each side
4x-15 = 7x
- Subtract 4x from each side
-15 = 3x
-5 = x
- Rewrite using symmetric property
<h2><u>
x = -5</u></h2>
Answer:
P2+p+4p+4
p(p+1)+4(p+1)
(p+4)(p+1)
p=-4 and p=-1
Step-by-step explanation:
it may help you to understand
The correct order would be:
5/64 x 3, 1/16 x 3, 3/32 x 4, 11/64 x 4, 7/16 x 3, 3/4 x 2, 3/8 x 4, 1 7/8 x 4, 2.25 x 2, 1.5 x 4, 3 3/8 x 3, 3.75 x 3
First we have to take all of the numbers and do the multiplication. It's often easiest to turn them in to decimals so that you have a common form.
3/32 x 4 = 3/8 = .375
3/4 x 2 = 3/2 = 1.5
1 7/8 x 4 = 15/4 = 3.75
2.25 x 2 = 4.5
1.5 x 4 = 6
3/8 x 4 = 3/2 = 1.5
5/64 x 3 = 5/32 = .156
3.75 x 3 = 11.25
1/16 x 3 = 3/16 = .1875
7/16 x 3 = 21/16 = 1.31
3 3/8 x 3 = 81/8 = 10.125
11/64 x 4 = 11/16 = .687
Now we can use those to put in order.
5/64 x 3 = 5/32 = .156
1/16 x 3 = 3/16 = .1875
3/32 x 4 = 3/8 = .375
11/64 x 4 = 11/16 = .687
7/16 x 3 = 21/16 = 1.31
3/4 x 2 = 3/2 = 1.5
3/8 x 4 = 3/2 = 1.5
1 7/8 x 4 = 15/4 = 3.75
2.25 x 2 = 4.5
1.5 x 4 = 6
3 3/8 x 3 = 81/8 = 10.125
3.75 x 3 = 11.25
Which if you are looking for without the extra terms, you can check the answer at the top.