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Andrews [41]
3 years ago
13

1. Find the vector represented by the directed line segment drawn from the point (3,5) to point B(-1,2). Also, find it's magnitu

de.
Your Answer:​
Mathematics
1 answer:
ella [17]3 years ago
5 0

Answer:

<em>Magnitude is 5</em>

Step-by-step explanation:

Using the formula for calculating the distance between two points expressed as:

D = √(x2-x1)²+(y2-y1)²

Given the coordinates  (3,5) and (-1,2)

D = √(2-5)²+(-1-3)²

D = √(-3)²+(-4)²

D = √9+16

D = √25

D = 5

<em>Hence the magnitude is 5</em>

<em></em>

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Y = 2 - 6x<br>17 y - x=1 solve the system​
Bond [772]

Answer:

(33/103,8/103)

In point form it is (33/103,8/103)

In equation form it is x = 33/103, y = 8/103

Hope this helps!

Consider giving brainliest. I only have 4 brainliest left and then my rank will go up.

7 0
3 years ago
Sergio passes by a bike store on Monday and sees his dream bike in the window. It cost 120 . He passes by on Wednesday and is th
insens350 [35]

Answer:

90

Step-by-step explanation:

120 - (120/4)

120 - 30 = 90

3 0
3 years ago
(21−3i)​ divided by (−3+9i)
MissTica

Answer:

Step-by-step explanation:

=\left(21\left(-3\right)-\left(-3\right)\cdot \:9\right)+\left(21\cdot \:9+\left(-3\right)\left(-3\right)\right)i

6 0
4 years ago
Find area of the isosceles triangle formed by the vertex and the x-intercepts of parabola y=x2+4x−12.
xz_007 [3.2K]

The area of the isosceles triangle is 64 sq units.

<u>Solution:</u>

Part 1: x-intercepts

The x-intercepts occur at the points on the function where y=0

So, we need to solve

x^2-4x-12=0

The left side factors fairly easily into:

(x-6)(x+2)=0

So solution occur when

x-6=0\rightarrow x=6

and

x+2=0\rightarrow x=(-2)

So the x-intercepts are at (0,6) and (0,−2)

Part 2: vertex of the parabola

The vertex of a simple quadratic parabola occurs when the derivative of the quadratic is equal to 0.

The derivative of the given quadratic is

\frac{dy}{dx}=2x-4

By observation, this is equal to 0 when x=2

When x=2 the original equation becomes

y=(2)^2-4(2)-12

y=-16

Therefore the vertex of this parabola is at (2,−16)

The endpoints of the base of the isosceles triangle are (-6, 0) and (2, 0)

\Rightarrow so its base is 8

The height of the triangle reaches from the midpoint of the base (-2, 0) and the vertex (2, -16)

\Rightarrow so its height is 16

The area is  \frac{1}{2}\times \text { base }\times \text { height }=\frac{1}{2}\times8\times16=64 \text{ sq units }

6 0
3 years ago
What is it this is due tomorrow HELP!!!
soldi70 [24.7K]

Hello from MrBillDoesMath!

Answer:

.04


Discussion:

1/25 =

(1*4)/(25*4) =

4/100 =

.04


Thank you,

MrB

8 0
3 years ago
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