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frosja888 [35]
3 years ago
12

The formula s= √SA/6 gives the length of the side, s, of a cube with a surface area, SA. How much longer is the side of a cube w

ith a surface area of 1,200 square inches than a cube with the surface area of 768 square inches?
Mathematics
2 answers:
amm18123 years ago
7 0
Surface area of cube = 6 * (side)^2
side^2 = surface area / 6
side = sqrt (surface area / 6)

For the cube with area 1200 square inches:
side = sqrt(surface area / 6)
side = sqrt(1200 / 6) 
side = 14.1421 inches

For the cube with area 768 square inches:
side = sqrt(surface area / 6) 
side = sqrt(768 / 6) 
side = 11.3137 inches

difference between the two lengths = 14.1421 - 11.3137 = 2.8284 inches

Based on the above calculations, the side of the cube with surface area 1200 square inches is  2.8284  inches longer than the side of the cube with surface area 768 square inches
kramer3 years ago
7 0

Answer:

B) 2√2 on edg.

Step-by-step explanation:

What the other person said but without the decimals :) enjoy

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Dmitriy789 [7]

On the line segment x=2, f depends only on y :

f(2,y) = g(y) = 4y^2 - 4y - 4

Find the critical points of g.

\dfrac{dg}{dy} = 8y - 4 = 0 \implies y = \dfrac12

At this critical point, we have

g\left(\dfrac12\right) = f\left(2,\dfrac12\right) = 3

Check the value of f at the endpoints of the line segment.

f\left(2,0\right) = 4

f\left(2,2\right) = 12

So we have

\min\left\{f(x,y) \mid x=2 \text{ and } 0 \le y \le 2\right\} = \boxed{3} \text{ at } (x,y) = \left(2,\dfrac12\right)

7 0
1 year ago
The hypotenuse of a right triangle is 5 meters longer than one of its legs. The other leg is 6 meters. Find the length of the ot
dedylja [7]

Answer:

Use Pythagorean theorm.

a^2 + b^2 = c^2 (c is hypotenuse).

Let c = 5+b (because in the question it says the hypotenuse is one leg plus 5 more meters) ; we will solve for b and say it's the leg we don't know.

We will say A is the "other leg" we know, which is 6.

6^2 + b^2 = (5+b)^2

We get b = 1.1

8 0
3 years ago
The equation of a hyperbola is x^2-4y^2-2x-15=0. What is the width of the asymptote rectangle?
zhenek [66]

Answer:  8

<u>Step-by-step explanation:</u>

x² - 2x  + ___ - 4y²  = 15 + ___

x² - 2x  + <u> 1 </u> - 4y²  = 15 + <u> 1 </u>

(x - 1)² - 4(y)² = 16

\frac{(x-1)^{2}} {16} - \frac{4(y - 0)^{2}}{16} = \frac{16}{16}

\frac{(x-1)^{2}} {16} - \frac{(y - 0)^{2}}{4} = 1

r_{x} = 4   r_{y} = 2

width of rectangle is 2(r_{x}) = 2(4) = 8

3 0
3 years ago
Find the value of x.<br> 7<br> Х<br> 3<br> Z<br> X =√[?]<br><br> Pls help explain !!
Vlad1618 [11]

Answer:

Answer:

 x = √70

Step-by-step explanation:

The triangles shown are all similar, so corresponding sides are proportional.

 hypotenuse/long side = x/7 = (7+3)/x

Cross-multiplying gives ...

 x^2 = 7(10)

 x = √70

_____

You will note that the value of x (the long side) is the geometric mean of the long segment and the whole hypotenuse.

A similar "geometric mean" relation holds for the short side:

 BC = √(CD·CA)

There is yet another "geometric mean" relation that holds for the altitude:

 BD = √(CD·AD)

Step-by-step explanation:

hope this helps

6 0
3 years ago
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