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Butoxors [25]
3 years ago
14

Need help with one can someone helppp me

Mathematics
1 answer:
son4ous [18]3 years ago
3 0

Answer:

it's 4

Step-by-step explanation:

take the given point and evaluate the x value in for x, and the y value for y, and simplify. If the equation is true, the point is a solution. if not, then it is not a solution.

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I am a square. My perimeter is 48 inches what is my area?
Fynjy0 [20]

Answer:

area=144

Step-by-step explanation:

so we need to find the length of each side

since its a square there is 4 sides

perimeter is all the sides added up

48/4=12

the formula for a squares are is b*h

12*12= 144

3 0
3 years ago
Read 2 more answers
Please help (-8) ^{-4}
katovenus [111]
(-8)^{-4}\\----------\\Use:\ a^{-n}=\frac{1}{a^n}\\-----------\\(-8)^{-4}=\frac{1}{(-8)^4}=\frac{1}{8^4}=\boxed{\frac{1}{4,096}}
5 0
4 years ago
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I NEED HELP!!<br><br> What is the interquartile range (IQR) of the data?
Tom [10]
What grade are you in? I don't believe I have learned this yet!

4 0
4 years ago
SEE QUESTION IN IMAGE
Alinara [238K]

Answer:

  • B. 48°

Step-by-step explanation:

∠OST = 90° as ST ⊥ OS (tangent is perpendicular to radius at same point)

m∠OSP = 1/2(180° - m∠SOP) = 90° - 96°/2 = 42° (sum of interior angles of the triangle SOP)

m∠PST = 90° - m∠OSP = 90° - 42° = 48° (angle addition postulate)

Correct choice is B

7 0
3 years ago
Anna is trying to save some money on her electric bill. Her electric company has come up with a new plan designed to charge cust
VMariaS [17]
First, we are going to calculate her monthly off-peak usage:
1,185 kWh - 500 kWh = 685 kWh

Now that we know her monthly electricity consumption is 500 kWh on-peak and 685 kWh off-peak, lets calculate the cost of each plan:
<span>Standard use plan
</span>1,185 kWh - 600 kWh = 585 kWh
- For the first 600 KWh:
 600kWh( \frac{8.5cents}{kWh} )=5100cents
Since 100 cents = 1 dollar, 5100cents( \frac{1dollar}{100cents} ) = $51
- For the remaining 585 kWh:
 585 kWh( \frac{11cents}{kWh} )=6435cents
Since 100 cents = 1 dollar, 6435cents( \frac{1dollar}{100cents}) = $64.35
Total cost of the standard use plan: $51 + $64.35 = $115.35

Interval use plan
- On-peak hours:
 500kWh( \frac{16cents}{1kWh} )=8000cents
Since 100 cents = 1 dollar, 8000cents( \frac{1dollar}{100cents} ) = $80
- Off-peak hours:
 685 kWh( \frac{4cents}{1kWh} )=2740cents
Since 100 cents = 1 dollar, 2740cents( \frac{1dollar}{100cents}) = $27.40
Total cost of the interval use plan: $80 + $27.40 = $107.40

We can conclude that:
1. The new interval plan will be better for Anna since she will save $7.95 per month in her electric bill.
2. The correct answer is: <span>b.standard use plan - $115.35; interval use plan - $107.40</span>
3 0
3 years ago
Read 2 more answers
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