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Anton [14]
4 years ago
6

A long solenoid (1 000 turns/m) carries a current of 25 mA and has an inside radius of 2.0 cm. A long wire which is parallel to

and 4.0 cm from the axis of the solenoid carries a current of 6.0 A. What is the magnitude of the magnetic field at a point on the axis of the solenoid

Physics
1 answer:
AlladinOne [14]4 years ago
7 0

Answer:

B=4.343 * 10⁻⁵ T

Explanation:

See attached photo for explanation.

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A 15.0 kg fish swimming at 1.10 m/s suddenly gobbles up a 4.50 kg fish that is initially stationary. Ignore any drag effects of
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Answer

given.

Mass of big fish = 15 Kg

speed of big fish = 1.10 m/s

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a) using conservation of momentum

m₁v₁ + m₂v₂ = (m₁+m₂) V

15 x 1.10 + 4.50 x 0 = (15 + 4.5)V

16.5 = 19.5 V

V = 0.846 m/s

b) Kinetic energy before collision

KE_1 = \dfrac{1}{2}m_1v_1^2 + \dfrac{1}{2}m_2v_2^2

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KE₁ = 9.075 J

Kinetic energy after collision

KE_2= \dfrac{1}{2}(15+4.5)\times 0.846^2

KE₂ = 6.98 J

Change in KE = 6.98 - 9.075 = -2.096 J

hence,

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