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andreyandreev [35.5K]
3 years ago
7

Raising the temperature of a gas will increase its pressure if the volume of the gas

Physics
1 answer:
ira [324]3 years ago
6 0
That would be C .............
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The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N
Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g  = 1.63 m/s^2

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

Weight=72 kg\times 1.63m/s^2=117.36 N

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0
4 years ago
Read 2 more answers
A car traveling at 22m/s is in an accident, and the 81 kg driver is brought to a stop in 1.4 s by in inflating airbag. What forc
larisa86 [58]
Here, F = m * a
F = m * v/t
Here, m = 81 Kg
v = 22 m/s
t = 1,4 s

Substitute their values, 
F = 81 * 22/1.4
F = 81 * 15.71
F = 1273 N
So, Closest value from your options is 1300 N

In short, Your Answer would be Option B

Hope this helps!
8 0
4 years ago
que 2. Why do we keep frequency constant instead of keeping vibrating length constam second law of vibrating string?​
ella [17]

Answer:

The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant

The law can be expressed mathematically as follows;

f = \dfrac{1}{2\cdot l} \cdot \sqrt{\dfrac{T}{m} }

The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously

Therefore, the law is verified indirectly, by rearranging the above equation as follows;

m = \dfrac{1}{ l^2} \cdot \dfrac{T}{4\cdot f^2} }

From which it can be shown that the following relation holds with the limits of error in the experiment

m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²

Explanation:

8 0
3 years ago
THE WINNER WILL BE AWARDED THE BRAINLIEST PLEASE HELPP
Ivenika [448]

Answer:Correct answer: 15.85 kg·m/s

Explanation:

A 30 kg gun is standing on a frictionless sur-face. The gun fires a 50 g bullet with a muzzlevelocity of 317 m/s.The positive direction is that of the bullet.Calculate the momentum of the bullet im-mediately after the gun was fired.

7 0
3 years ago
Which of the following is not a transverse wave?A) soundB) lightC) radioD) all of theseE) none of these
quester [9]
The answer is light, because a transverse wave is a wave vibrating at right angles to the direction of its propagation
7 0
3 years ago
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