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andrew11 [14]
3 years ago
12

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

ill you find between weight and mass in your measurements?
A. They are equal.
B. Weight is directly proportional to mass.
C.Weight is inversely proportional to mass.
D. Mass equals weight times acceleration due to gravity.
Physics
2 answers:
mario62 [17]3 years ago
4 0
<span>Weight is directly proportional to mass.</span>
jekas [21]3 years ago
3 0
Hey there! Hello!

So, for this problem, we need to keep in mind what the formula for calculating mass is in the case of given acceleration and weight.

W=Weight
a=acceleration (gravitational pull)
m=mass

W=am, so
m=W/a.

Lets go through the answers:

A is incorrect right off the bat, since it's impossible for there to be circumstances that allow for both weight and mass to be equal.

B sounds like the right one to me, as the weight will affect the mass directly if the acceleration doesn't change (which is why they made it known that this was from one location), and vice versa.

C isn't correct, since it's basically saying the opposite of what actually happens occurs (weight goes up, mass goes down, and vice versa).

D has also been disproven based on our formula above. Weight is the one that equals mass times acceleration, not the other way around.

I hope this helps you out! Feel free to ask me any additional questions if you have any. :-)
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elixir [45]

Given that,

Distance, d = 10700 km

Time taken by the airplane to complete the destination, t = 12 hours

We need to find the speed of the airplane. It is equal to the total distance covered divided by total time taken. So,

v=\dfrac{d}{t}\\\\v=\dfrac{10700\ km}{12\ h}\\\\v=891.66\ km/h

We know that,

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So,

v=891.66\ km/h =\dfrac{891.66\times 1000\ m}{3600\ s}\\\\v=247.68\ m/s

So, the speed of the airplane is 891.66 km/h or 247.68 m/s.

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A 2.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0300 m . The spring has
iogann1982 [59]

Answer:

v = 0.41 m/s

Explanation:

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  • At any point, the total mechanical energy is the sum of the kinetic energy plus the elastic potential energy.
  • So, we can write the following general equation, taking the initial and final values of the energies:

       \Delta K + \Delta U = W_{ffr}  (1)

  • Since the block and spring start at rest, the change in the kinetic energy is just the final kinetic energy value, Kf.
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  • The change in the potential energy, can be written as follows:

       \Delta U = U_{f}  - U_{o}  = \frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (3)

       where k = force constant = 815 N/m

       xf = final displacement of the block = 0.01 m (taking as x=0 the position

      for the spring at equilibrium)

      x₀ = initial displacement of  the block = 0.03 m

  • Regarding the work done by the force of friction, it can be written as follows:

       W_{ffr} = - \mu_{k}* F_{n} * \Delta x  (4)

       where μk = coefficient of kinettic friction, Fn = normal force, and Δx =

       horizontal displacement.

  • Since the surface is horizontal, and no acceleration is present in the vertical direction, the normal force must be equal and opposite to the force due to gravity, Fg:
  • Fn = Fg= m*g (5)
  • Replacing (5) in (4), and (3) and (4) in (1), and rearranging, we get:

        \frac{1}{2} * m* v^{2} = W_{ffr} - \Delta U = W_{ffr} - (U_{f} -U_{o})  (6)

        \frac{1}{2} * m* v^{2} = (- \mu_{k}* m*g* \Delta x)  -\frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (7)

  • Replacing by the values of m, k, g, xf and x₀, in (7) and solving for v, we finally get:

    \frac{1}{2} * 2.00 kg* v^{2}  = (-0.4*2.00 kg*9.8m/s2*0.02m) +( (\frac{1}{2} *815 N/m)* (0.03m)^{2} - (0.01m)^{2}) = -0.1568 J + 0.326 J (8)

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nalin [4]

Explanation:

It s given that,

Mass of a planet, M=3.7\times 10^{24}\ kg

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g=\dfrac{GM}{R^2}

g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}

g=2.91\ m/s^2

(2) The escape velocity is given by :

v=\sqrt{\dfrac{2GM}{R}}

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aleksandrvk [35]

Answer:

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