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andrew11 [14]
3 years ago
12

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

ill you find between weight and mass in your measurements?
A. They are equal.
B. Weight is directly proportional to mass.
C.Weight is inversely proportional to mass.
D. Mass equals weight times acceleration due to gravity.
Physics
2 answers:
mario62 [17]3 years ago
4 0
<span>Weight is directly proportional to mass.</span>
jekas [21]3 years ago
3 0
Hey there! Hello!

So, for this problem, we need to keep in mind what the formula for calculating mass is in the case of given acceleration and weight.

W=Weight
a=acceleration (gravitational pull)
m=mass

W=am, so
m=W/a.

Lets go through the answers:

A is incorrect right off the bat, since it's impossible for there to be circumstances that allow for both weight and mass to be equal.

B sounds like the right one to me, as the weight will affect the mass directly if the acceleration doesn't change (which is why they made it known that this was from one location), and vice versa.

C isn't correct, since it's basically saying the opposite of what actually happens occurs (weight goes up, mass goes down, and vice versa).

D has also been disproven based on our formula above. Weight is the one that equals mass times acceleration, not the other way around.

I hope this helps you out! Feel free to ask me any additional questions if you have any. :-)
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WOULUJUTUL RECIPECUIUS.
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The force between the two objects is 19.73 nN.

<u>Explanation: </u>

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider M_{1} and M_{2} as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

                      \text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}

As gravitational constant G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}, M_{1} = 20 kg and  M_{2} = 100 kg, while d = 2.6 m, then

                    \text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}

Thus, we get finally,

                   \text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}

As we know, nano denoted by letter 'n' equals to 10^{-9}

So the force acting between two objects is 19.73 nN.

7 0
2 years ago
The strength of an electromagnet can be altered by
denpristay [2]
The strength of an electromagnet can be altered by increasing the number of coils around the core. The more times the coil is wrapped, the stronger the electromagnet is.

Your answer is: B) Increasing the number of coils around the core 

Have an amazing day and stay hopeful!

3 0
3 years ago
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What is the scientific term for rocks formed from lava?
sergeinik [125]

Answer:

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3 years ago
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2 years ago
A penny is dropped off the top of the Stratosphere from rest and falls freely with the
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Answer:

S = 122.5m

Explanation:

Given the following data;

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Since it's a free fall, initial velocity, u = 0

To find the displacement, we would use the second equation of motion given by the formula;

S = ut + \frac {1}{2}at^{2}

Where;

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Substituting into the equation, we have;

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