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andrew11 [14]
3 years ago
12

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

ill you find between weight and mass in your measurements?
A. They are equal.
B. Weight is directly proportional to mass.
C.Weight is inversely proportional to mass.
D. Mass equals weight times acceleration due to gravity.
Physics
2 answers:
mario62 [17]3 years ago
4 0
<span>Weight is directly proportional to mass.</span>
jekas [21]3 years ago
3 0
Hey there! Hello!

So, for this problem, we need to keep in mind what the formula for calculating mass is in the case of given acceleration and weight.

W=Weight
a=acceleration (gravitational pull)
m=mass

W=am, so
m=W/a.

Lets go through the answers:

A is incorrect right off the bat, since it's impossible for there to be circumstances that allow for both weight and mass to be equal.

B sounds like the right one to me, as the weight will affect the mass directly if the acceleration doesn't change (which is why they made it known that this was from one location), and vice versa.

C isn't correct, since it's basically saying the opposite of what actually happens occurs (weight goes up, mass goes down, and vice versa).

D has also been disproven based on our formula above. Weight is the one that equals mass times acceleration, not the other way around.

I hope this helps you out! Feel free to ask me any additional questions if you have any. :-)
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A vector is 14.4 m long and
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Explanation:

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3 years ago
A 70 kg hunter, standing on frictionless ice, shoots a 42 g bullet horizontally at a speed of 590 m/s . Part A Part complete Wha
Kisachek [45]

Answer:

The recoil velocity is 0.354 m/s.

Explanation:

Given that,

Mass of hunter = 70 kg

Mass of bullet = 42 g = 0.042 kg

Speed of bullet = 590 m/s

We need to calculate the recoil speed of hunter

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

Where,m_{1} = mass of hunter

m_{2} = mass of bullet

u = initial velocity

v = recoil velocity

Put the value in the equation

0+0=70\times v_{1}+0.042\times590

v_{1}=-\dfrac{0.042\times590}{70}

v=-0.354\ m/s

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8 0
3 years ago
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Mashutka [201]

Answer:

She covers the distance is 12 km.

The magnitude of displacement is 8.6 km.

The direction of her displacement is north east.

Explanation:

Given that,

Christina drives his moped 7 kilometers North and stop for lunch and then drive 5 km east.

We need to calculate the total distance

Using formula of distance

d=d_{1}+d_{2}

Put the value into the formula

d=7+5

d=12\ km

We need to calculate the magnitude of displacement

Using formula of displacement

D=xi+yj

D=5i+7j

D=\sqrt{5^2+7^2}

D= 8.6\ km

The direction of her displacement is north east.

Hence, She covers the distance is 12 km.

The magnitude of displacement is 8.6 km.

The direction of her displacement is north east.

6 0
3 years ago
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