Here, we know, according to 3rd Equation of Kinematics,
v² - u² = 2as
Here, u = 0 [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m
Substitute their values,
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s
In short, Your Answer would be Option D
Hope this helps!
Answer:
I = 2 MR²
Explanation:
Given that
Radius of the hollow ring ( hoop ) = R
The mass of the hoop = M
We know that mass moment of inertia of a hoop about its center is given as
Io= M R²
By using theorem ,mass moment of inertia at distance d from center is given as
I= Io + m d²
Here ,M= m ,d =R
Now by putting the values in the above equation we get
I = M R² + M R²
I = 2 MR²
Therefore the mass moment of inertia will be 2 M R².
Given:
f = 1160 kHz = 1160 x 10³ Hz
The velocity is c = 3 x 10⁸ m/s, the velocity of light (approximmately).
Calculate the wavelength, λ.
c = fλ
λ = c/f = (3 x 10⁸ m/s)/(1160 x 10³ 1/s) = 258.62 m
Answer: 258.6 m
A (n) conductor is a material that transfers heat well
Hope that helped
