Write –2x2(–5x2 + 4x3) in standard form

Mathematics

1 answer:

aksik [14]4 years ago

3 0

We open the brackets

And use the laws of indices

-2x^2(-5X^2+4X^3)

Opening brackets

10X^4-8X^5 we get X^4 and X^5 because the terms we have multiplied have common bases and therefore we have added the powers

Hence our answer is 10X^4-8X^5

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Proove that <br>1/1-sin theta + 1/1+cos theta = 2×sec square theta

Rina8888 [55]

Step-by-step explanation:

We need to prove that,

$\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}=2\times \sec^2\theta$

Taking LHS,

$\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}\\\\=\dfrac{(1+\sin\theta)+(1-\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}\\\\=\dfrac{2}{1-\sin^2\theta}\\\\\text{As}\ 1-\sin^2\theta=\cos^2\theta\\\\=\dfrac{2}{\cos^2\theta}\\\\\text{As}\ \dfrac{1}{\cos^2\theta}=\sec^2\theta\\\\=2\sec^2\theta\\\\=RHS$