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adell [148]
2 years ago
14

X and Y intercepts of y=1/3x

Mathematics
1 answer:
saul85 [17]2 years ago
5 0

Answer:

y=1/3x

y int : y=1/3(0)

=(0, 0)

x-int : 0=1/3x

x = 0

(0, 0)

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Like terms and unlike terms
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Answer:

In algebra, like terms are terms that have the same variables and powers. The coefficients do not need to match.

Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power. For example, 8xyz2 and −5xyz2 are like terms because they have the same variables and power while 3abc and 3ghi are unlike terms because they have different variables. Since the coefficient doesn't affect likeness, all

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4 years ago
Read 2 more answers
What two numbers add to get 4 and multiply to get -4
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-2 and -2 Two negatives added equal a positive.............. . . .. . . . . . . 
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3 years ago
5/6-1/8 Solve by finding a common denominator<br><br> A)30/48<br> B)34/48<br> C)38/48<br> D)42/48
GrogVix [38]

Answer:

  B)  34/48

Step-by-step explanation:

The easiest common denominator to find is the product of the denominators you have.

__

The difference is ...

  \dfrac{5}{6}-\dfrac{1}{8}=\dfrac{5}{6}\cdot\dfrac{8}{8}-\dfrac{1}{8}\cdot\dfrac{6}{6}\\\\=\dfrac{40-6}{48}=\boxed{\dfrac{34}{48}}

__

<em>Additional comment</em>

The difference numerator and denominator have a common factor of 2, so can be reduced to 17/24. The denominator 24 could have been used as the common denominator from the start.

  5/6 -1/8 = 20/24 -3/24 = 17/24 . . . . reduced result

__

Using the <em>least common denominator</em> does not always result in a reduced sum or difference. If some other denominator is used (as here), then you can be assured that the result will need to be reduced to get to lowest terms.

8 0
2 years ago
The Martinez family went to the movies and paid $60 for two adult tickets and three children’s tickets. The Wright family consis
Pepsi [2]

Answer:

a = $13.5

Step-by-step explanation:

Let a = adult tickets

Let c = children tickets

Translating the word problem into an algebraic equation;

<u>For the Martinez family;</u>

2a + 3c = $60

<u>For the Wright family;</u>

3a + 5c = $95.5

Thus, the simultaneous equations are;

2a + 3c = $60 ..........equation 1

3a + 5c = $95.5 .........equation 2

We would use substitution method to solve;

From equation 2, we make a the subject of formula;

3a = 95.5 - 5c

a = (95.5 - 5c)/3

<em>Substituting the value of "a" into equation 1, we have;</em>

2[(95.5-5c)/3] + 3c = 60

Multiplying all through by 3;

2(95.5 - 5c) + 9c = 180

191 - 10c + 9c = 180

191 - c = 180

c = 191-180

c = $11

To find the value of a;

2a +3c = 60

<em>Substituting the value of "c" into the equation, we have;</em>

2a + 3(11) = 60

2a + 33 = 60

2a = 60 - 33

2a = 27

a = \frac{27}{2}

a = $13.5

<em>Therefore, the cost of an adult movie ticket is $13.5. </em>

5 0
3 years ago
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