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amm1812
3 years ago
8

JK has endpoints at J(5,9) and K(7, 7). Find the midpoint M of JK.

Mathematics
2 answers:
Basile [38]3 years ago
5 0

Answer:

J (7, 10)

K (3, 2)

Formula for midpoint:

x - coordinate for M:

y - coordinate for M:

Therefore, M (5,6).

Hope this helps :)

Step-by-step explanation:

Aleksandr-060686 [28]3 years ago
5 0

Answer:

(6,8  )

Step-by-step explanation:

Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}  )

Simply plug in your coordinates into the midpoint formula to find midpoint:

(\frac{5+7}{2},\frac{9+7}{2}  )

(\frac{12}{2},\frac{16}{2}  )

(6,8  )

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Answer:

The median is 29

Step-by-step explanation:

So you have to cross out 12 then 2 then 33 then 4 then 18 then 17 then 28 then 12 and the last number that's standing is 29.

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Pizza Time has collected data about customer pizza topping preferences. They have calculated that P(pepperoni) = 0.7, P(olives)
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3 years ago
An animal reserve has 40,000 elk. The population increases 11% a year. How long tell the population is equal to 80,000. If someo
sukhopar [10]

Answer:

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Step-by-step explanation:

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3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

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\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

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(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

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You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
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I would say a Coordinate Grid.

5 0
3 years ago
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