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2 years ago

The constant in the expression-2x is?

Mathematics

1 answer:

Kryger [21]2 years ago

8 0

Answer:

-2

Step-by-step explanation:

Well if we break -2x apart we see that it's really just -2 × x.

Now, let's say you completely forget this you can think of it like this:

-2x is, -2 and x.

Between these two terms x is the variable leaving -2.

You can try the same thing with these:

5x is ?

-9x is ?

50x is ?

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Which system of linear inequalities is represented by the<br> graph?

Nikitich [7]

Answer:

Step-by-step explanation:

Easiest and fastest way to determine your answer is to graph the systems of inequalities on a graphing calc. Once you do so, you should be able to see that Choice C is the correct answer.

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3 years ago

Bennett and his friends decide to go bowling. The cost for the group is $15 for shoe rentals plus $4.00 per game. a. How much wi

vampirchik [111]

8 for 2 games plus the shoe rentals (15)make it 23 for 2games
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2 years ago

Lana wants to buy a hamster. The hamster is on sale for 19% off. Lana has a coupon as well. The coupon is for 15% off. What is t

son4ous [18]

Answer:

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Step-by-step explanation:

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2 years ago

7/9% of 1 is equal to what fraction of the quantity

swat32

7/9% is not 7/9 of 1, it's 7/9 of 0.01.

So, it is 0.0078

Hope this helps!

6 0

2 years ago

A random sample of 64 observations produced a mean value of 84 and standard deviation of 5.5. The 90% confidence interval for th

ASHA 777 [7]

Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

Step-by-step explanation:

When population standard deviation is not given ,The confidence interval population proportion is given by ( $\mu$ ):-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where n= Sample size.

s= Sample standard deviation

$\overline{x}$ = sample mean

t* = Critical t-value (Two-tailed)

As per given , we have

$\overline{x}=84$

n= 64

Degree of freedom : df = n-1=63

s= 5.5

Significance level : $\alpha=1-0.90=0.1$

Two-tailed T-value for df = 63 and $\alpha=1-0.90=0.1$ would be

$t_{\alpha/2,df}=t_{0.05,63}=1.669$ (By t-distribution table)

i.e. t*= 1.669

The 90% confidence interval for the population mean μ would be

$84\pm (1.669)\dfrac{5.5}{\sqrt{64}}$

$=84\pm (1.669)\dfrac{5.5}{8}$

$\approx84\pm 1.15$

$=(84-1.15,\ 84+1.15)=(82.85,\ 85.15)$

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

6 0

3 years ago