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andriy [413]
3 years ago
14

Is 1/2 between 0.1 and 0.2?

Mathematics
1 answer:
Nady [450]3 years ago
3 0
No, 1/2=0.5


This is because half of one is 0.5, since 0.5 x 2 = 1.

0.1 written as a fraction would be 1/10, since 0.1 x 10 = 1.
0.2 written as a fraction would be 1/5, since 0.2 x 5 = 2
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Please help asap with this question i will give brainliest.
HACTEHA [7]

Answer:

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = ( - \frac{1}{5}, \frac{1}{3} ) and r = \frac{1}{2}, thus

(x - (- \frac{1}{5} ))² + (y - \frac{1}{3} )² = ( \frac{1}{2} )², that is

(x + \frac{1}{5} )² + (y - \frac{1}{3} )² = \frac{1}{4} → D

7 0
3 years ago
PLEASE CAN SOMEONE HELP????
schepotkina [342]

Answer:

figure it out dummy

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is 30% as a fraction
krok68 [10]
 = 30%

= 0.3

= 3/10

Hope this helps.
4 0
2 years ago
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Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0
2 years ago
Hiii please help if you give a correct answer i’ll give brainliest thanks!
vovangra [49]
Answer: B and D

Explanation:
5 0
3 years ago
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