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Minchanka [31]
3 years ago
8

An ice cube of volume 15 cm^3 and density 917 kg/m^3 is placed in ethyl alcohol of density 811 kg/m^3. What is the buoyant force

on the ice? Will it float?
Physics
1 answer:
Amiraneli [1.4K]3 years ago
3 0

Answer:

the buoyant force acting on the  ice cube is 0.119 N

Explanation:

given,

volume of ice cube = 15 cm³ = 15 × 10⁻⁶ m³

density of ice cube = 917 kg/m³

density of ethyl alcohol = 811 kg/m³

buoyant force = ?

The density of ice is more than ethyl alcohol hence it will sink.

buoyant  force acting on the ice cube = ρ V g

                                                                = 811 × 15 × 10⁻⁶ × 9.81

                                                                =0.119 N

so, the buoyant force acting on the  ice cube is 0.119 N

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