Answer:

Explanation:
Mass of the Sun, 
The radius of the Sun, 
We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

So, the value of acceleration due to gravity on the Sun is
.
Bacteria( cholera)
Virus( AIDS)
Fungi(athlete's foot)
Protist( malaria)
Pleasssssssse mark me as brainliest
Answer:
Statement 2 is wrong
Explanation:
To check the statements in this exercise, let's describe the main properties of electromagnetic waves. Let's describe the characteristics
* they are transverse waves
* formed by the oscillations of the electric and magnetic fields
* the speed of the wave is the speed of light
with these concepts let's review the final statements
1) True. Formed by the oscillation of the two fields
2) False. They are transverse waves
3) True. Can travel by vacuum as they are supported by oscillations of the electric and magnetic fields
4) True. They all have the same speed of light
Statement 2 is wrong
Answer:
(a) The magnetic energy density in the field is 6.366 J/m³
(b) The energy stored in the magnetic field within the solenoid is 5 kJ
Explanation:
magnitude of magnetic field inside solenoid, B = 4 T
inner diameter of solenoid, d = 6.2 cm
inner radius of the solenoid, r = 3.1 cm = 0.031 m
length of solenoid, L = 26 cm = 0.26 m
(a) The magnetic energy density in the field is given by;

(b) The energy stored in the magnetic field within the solenoid

