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3 years ago

Is 5 a solution to 2x + 5 = 15? Yes or No How do you know?

Mathematics

2 answers:

dybincka [34]3 years ago

5 0

Answer:

Step-by-step explanation:

tankabanditka [31]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

yes because when you place 5 in the x spot you arrive a final answer of 15=15

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Can someone walk me through how to do this problem please?

Sholpan [36]

Hey!

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We Know:

m∠AED = 34°

m∠EAD = 112°

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Solution:

You notice 4 small triangles in both triangles. That shows that both triangles are the same.

The angles are the same for m∠BDC and m∠AED.

The angles are the same for m∠ADB and m∠EAD

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Angles:

m∠BDC = 34°

m∠ADB = 112°

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Congruent Angles:

m∠AED ≡ m∠BDC

m∠EAD ≡ m∠ADB

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Hope This Helped! Good Luck!

5 0

3 years ago

Which comes first? Intermediate algebra, or algebra?

xxTIMURxx [149]

Answer

Algebra

Step-by-step explanation:

Intermediate is the same as algebra 2

4 0

3 years ago

Read 2 more answers

Rosa has $117 in her savings account and $95 in her checking account. Each week she will put $21 into her savings account and $2

mr_godi [17]

Answer:

It will take Rosa 5 and a half (5.5) weeks to have the same amount of money in both accounts.

Step-by-step explanation:

For this problem, we will have to set two expressions equal to each other. The first expression will represent Rosa's saving account, which already has $117 in it. Every week ( $x$ ), she adds $21 to her savings account:

$21x+117$

The second expression will represent Rosa's checking account. Rosa's checking account already has $95 in it. Every week ( $x$ ), she adds $25 to her checking account:

$25x+95$

Now that we have our two expressions, set them equal to each other. This is our equation that will be used to find the number of weeks ( $x$ ) it takes until Rosha has the same amount of money in both accounts:

$21x+117=25x+95$

Subtract $21x$ from both sides of the equation:

$117=4x+95$

Subtract $95$ from both sides of the equation:

$22=4x$

Divide both sides of the equation by the coefficient of $x$ , which is $4$ :

$5.5=x$

$x=5.5$

So it will take five and a half weeks for her accounts to have the same amount of money.

Check your work by substituting $5.5$ into the initial equation:

$21(5.5)+117=25(5.5)+95$

$115.5+117=137.5+95$

$232.5=232.5$

Since the accounts have the same amount, the answer is correct!

6 0

3 years ago

Read 2 more answers

Write an equation in point slope form of the line that passes through the point (6,-5) and has the slope 1/2

babymother [125]

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

$y - y_1 = m(x - x_1)$

where

m is the slope

( x1 , y1) is the point

From the question we have the final answer as

$\huge y + 5 = \frac{1}{2} (x - 6) \\$

Hope this helps you

5 0

2 years ago

Read 2 more answers

find the coordinates of the point P on the parabola y=1-x^2 with domain 0≤x≤1 that minimize the area of the triangle enclosed by

coldgirl [10]

Let point P be with coordinates $(x_0,y_0).$ Find the equation of the tangent line.

1. If $y=1-x^2,$ then $y'=-2x.$

2. The equation of the tangent line at point P is

$y-y_0=-2x_0(x-x_0).$

Find x-intercept and y-intercept of this line:

when x=0, then $y=y_0+2x_0^2;$
when y=0, then $x=\dfrac{y_0}{2x_0}+x_0=\dfrac{y_0+2x_0^2}{2x_0}.$

The area of the triangle enclosed by the tangent line at P, the x-axis, and y-axis is

$A=\dfrac{1}{2}\cdot (2x_0^2+y_0)\cdot \left(\dfrac{y_0+2x_0^2}{2x_0}\right)=\dfrac{(y_0+2x_0^2)^2}{4x_0}.$

Since point P is on the parabola, then $y_0=1-x_0^2$ and

$A=\dfrac{(1-x_0^2+2x_0^2)^2}{4x_0}=\dfrac{(1+x_0^2)^2}{4x_0}.$

Find the derivative A':

$A'=\dfrac{2(1+x_0^2)\cdot 2x_0\cdot 4x_0-4(1+x_0^2)^2}{16x_0^2}=\dfrac{12x_0^4+8x_0^2-4}{16x_0^2}.$

Equate this derivative to 0, then

$12x_0^4+8x_0^2-4=0,\\ \\3x_0^4+2x_0^2-1=0,\\ \\D=2^2-4\cdot 3\cdot (-1)=16,\ \sqrt{D}=4,\\ \\x_0^2_{1,2}=\dfrac{-2\pm4}{6}=-1,\dfrac{1}{3},\\ \\x_0^2=\dfrac{1}{3}\Rightarrow x_0_{1,2}=\pm\dfrac{1}{\sqrt{3}}.$

And

$y_0=1-\left(\pm\dfrac{1}{\sqrt{3}}\right)^2=\dfrac{2}{3}.$

Answer: two points: $P_1\left(-\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right), P_2\left(\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right).$

6 0

3 years ago