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emmainna [20.7K]
3 years ago
5

Results of a poll stated that 40% of U.S. adults identify as Republican, and you want to test the claim at alpha = 0.05. What le

vel of confidence should you use? (Answer to two decimal places, e.g., 0.75).
Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer:

The confidence level is 95% or 0.95.

Step-by-step explanation:

Consider the provided information.

Results of a poll stated that 40% of U.S.

If you want to test the claim at alpha = 0.05.

As we know:

Confidence level = 1 - significance level (\alpha)

Confidence level = 1 - 0.05

Confidence level  = 0.95

Therefore, the confidence level is 95% or 0.95.

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Persons taking a​ 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
mihalych1998 [28]

Answer:

y = 4.125x + 496.25

Step-by-step explanation:

Set the data up as points. Then deal with the points.

Givens

(30,620)

(70,785)

y2 = 785

y1 = 620

x2 = 70

x1 = 30

Formula

Slope = (y2 - y1) / (x2 - x1)

Solution

Slope = (785 - 620)/(70 - 30)

Slope = 165 / 40

Slope = 4.125

===================

Now you need the y intercept. Either one of the two given points will give you that.

y = 620

x = 30

m = 4.125

y = mx + b

620 = 4.125*30 + b

620 = 123.75 + b

620 - 123.75 + b

b = 496.25

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3 years ago
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vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
EXTRA POINTS! volume of spheres.
BartSMP [9]

Answer:

V≈33.51

although I don't have an explanation, sorry, if you look up "how to find the volume of a sphere" on google, it will give you the answer

3 0
3 years ago
Can you solve this I am confused
mr Goodwill [35]
The answer is B and C. Hope this helps!
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99 times the sum of v and 9
pav-90 [236]
99 (v + 9) is the answer
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