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2 years ago

PLEASE HELP!!!!!! I NEED THIS ASAP

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

6 0

Answer:

11.2

Step-by-step explanation:

PYTHAGOREAN THEOREM

14^2 = 8.4^2 + x^2

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Which fraction has a value that's equal to 3⁄4? A. 12⁄16 B. 12⁄12 C. 4⁄3 D. 9⁄16

Rus_ich [418]

The fraction 12/16 has the same .75 value as the fraction 3/4

8 0

3 years ago

Read 2 more answers

The number of students who chose lunch was 5 more than the number of students who chose breakfast. Write a system of linear equa

Papessa [141]

Answer:

The system of linear equations are $y=5+x$ and $x+y=25$

Step-by-step explanation:

Given : The number of students who chose lunch was 5 more than the number of students who chose breakfast. Let x represent the number of students who chose breakfast and y represent the number of students who chose lunch.

(50 students picked, 25 picked dinner the rest picked lunch and breakfast)

To find : Write a system of linear equations that represents the numbers of students who chose breakfast and lunch ?

Solution :

The number of students who chose breakfast be 'x'

The number of students who chose lunch be 'y'.

The number of students who chose lunch was 5 more than the number of students who chose breakfast.

i.e. $y=5+x$

Now, Total student were 50 and 25 picked dinner the rest picked lunch and breakfast i.e. 25.

So, $x+y=25$

Therefore, the system of linear equations are $y=5+x$ and $x+y=25$

4 0

2 years ago

Verdadero o falso: Q (números racionales) ∩ I (números irracionales) = Ø. Porque?

ozzi

Answer:

I think true but can u translate to english so I could understand

7 0

2 years ago

HELP WILL GIVE YOU Brainiest!!!

Phoenix [80]

Answer:

Step-by-step explanation:

So there we have it, <A=135° and <B=45°. This should check when you add them together ("<A and <B are supplementary which means that together their angles equal 180°"). Does 135°+45=180°? YES!

I Really hope it helps

8 0

2 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

1 year ago