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Liono4ka [1.6K]
3 years ago
7

Let mAngleA = 40°. If AngleB is a complement of AngleA, and AngleC is a supplement of AngleB, find these measures. mAngleB = ° m

AngleC = °
Mathematics
2 answers:
kati45 [8]3 years ago
6 0

Answer:

B is 50° and C is 130°

Step-by-step explanation:

complementary angle

x+x=90°

40°+x=90°

x=90°-40°

x=50°

supplementary angles

x+x=180

50+x=180

x=180-50

x=30°

Ilia_Sergeevich [38]3 years ago
3 0

Answer:

m<B 50     m<C 130

Step-by-step explanation:

i jus did it :)

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Suppose you have 62 feet of fencing to go around a rectangular flower garden. You want
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Answer:

Answer is 9 feet = 9 fe 2t

w= 9fe 2t

Step-by-step explanation:

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3 years ago
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If the volume of a cone is 12.56, and the height is 3. What is the radius of the cone? R=
Alina [70]

Answer:

you can find a radius through its volume and height. Multiply the volume by 3. For example, the volume is 20. Multiplying 20 by 3 equals 60

Step-by-step explanat                      

I hope to help you

5 0
2 years ago
Find the surface area of a cone with radius 14.2 inches and slant height 24.1 inches.
ololo11 [35]

Answer:

1708.58658058

Step-by-step explanation:

Total surface area formula = (π×r²)+(π×r×s)

r = radius

s = slant height

So we substitute the values into the formula (π×r²)+(π×r×s)

(π×14.2²)+(π×14.2×24.1) = 1708.58658058

8 0
3 years ago
The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

7 0
3 years ago
Resta -7/10 -(-4/15)
Snezhnost [94]

Answer:

-13/30

Step-by-step explanation:

I used KCC. It is a method when you<u> keep you 1st # the same</u>, <u>change subtraction to addition</u> and then <u>change the last # to its opposite.</u> So after KCC, the equation would be -7/10 + 4/15

6 0
3 years ago
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