The resulting number would be 120
Answer:
Data: for the 10 days of practice, we have:
0.5 hours 1 time.
0.75 hours 2 times
1 hour 3 times
1.25 hours 2 times
1.5 hours 1 time
2 hours 1 time.
A) the largest amount number of times that she practiced by the same amount of time is 3 (for the 1-hour practice)
The smallest is 1 ( for the 0.5h, 1.5h, and 2h practices)
the difference is 3 - 1 = 2.
B) the time that she practiced more times is 1 hour, she practiced that amount of time in 3 different days out of the 10 days.
C) the equation can be found by multiplying the number of hours by the number of times that she practiced that amount of time, and then adding all of them:
0.5h*1 + 0.75h*2 + 1h*3 + 1.25h*2 + 1.5h*1 + 2h*1
D) the solution for the previous equation is 11 hours. Here the correct option is A.
5+5=10
15-5=10
5x2=10
20/2=10
10^1 (10 to the power of 1) or 0.1^-1 (0.1 to the power of -1)
Answer:
0 x anything = 0
Step-by-step explanation:
Anything multiplied by 0 = 0
9514 1404 393
Answer:
1 < 15 -2a < 7
Step-by-step explanation:
There are a couple of ways you can do this.
1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:
15-2a for a=4:
15-2(4) = 7
15-2a for a=7:
15-2(7) = 1
Then ...
1 < 15-2a < 7
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2) Solve for a in terms of the value of 15-2a, then impose the limits on a.
x = 15 -2a
2a = 15 -x
a = (15 -x)/2
Now, impose the given limits:
4 < (15 -x)/2 < 7
8 < 15 -x < 14 . . . multiply by 2
-7 < -x < -1 . . . . . . subtract 15
7 > x > 1 . . . . . . . . multiply by -1
1 < 15-2a < 7 . . . . . use x=15-2a
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The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.
