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Alinara [238K]
3 years ago
7

You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.

Mathematics
2 answers:
Sloan [31]3 years ago
5 0

Answer: for question 2, 3 and 4 on that page the answers are 2. -3/13 points: no you should not play the game . 3. E(X)=0 4. 12

Step-by-step explanation:

Andreyy893 years ago
3 0

Answer:

a = 9\\b = 48\\c = -1

Step-by-step explanation:

We know that:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

E(V) = VP(V)

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

Therefore, expected value for V, the number of points obtained in the game is:

E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)

So:

a = 9\\b = 48\\c = -1

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