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Maurinko [17]
3 years ago
14

The first term of an arithmetic sequence is 14. The 25th term is 206. What is the common difference of the arithmetic sequence?

Mathematics
2 answers:
larisa [96]3 years ago
3 0

an = a1+ d(n-1)

a1 =14

an=206  when n=25

206 = 14 + d (25-1)

206 = 14 + d * 24

subtract 14 from each side

192 = 24d

divide by 24 on each side

d=8

The common difference is 8

REY [17]3 years ago
3 0

an atirmetic sequence  can be written in form

a_n=a_1+d(n-1)

where a_n is the nth term

a_1 is the first term

d is the common difference

n is the counter variable


so, given that first term is 14 (a_1=14) and given taht 25th term is 206 (a_{25}=206), we want to find d


a_{25}=206

a_{25}=a_1+d(25-1)

206=14+24d

minus 14 both sides

192=24d

divide both sides by 24

8=d

the common difference is 8

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erik [133]

Answer:

number of hours  Alexander family ‘s sprinkler work = 20

number of hours  Morgan family ‘s sprinkler work = 30

Step-by-step explanation:

Given in the question,

water output rate for the Alexander family ‘s sprinkler = 40 L  

water output rate for the Morgan family ‘s sprinkler = 20 L

Suppose, number of hours  Alexander family ‘s sprinkler work = x

Suppose, number of hours  Morgan family ‘s sprinkler work = y

Equation1

x + y = 50

Equation 2

40x + 20y = 1400

x = 50 - y

Put this value of x in equation 2

40(50-y) + 20y = 1400

2000 - 40y + 20y = 1400

-20y = 1400 - 2000

-20y = -600

y = 30

Put this value of y in equation 1 to get the value of x

x + 30 = 50

x = 50 - 30

x = 20

 

5 0
3 years ago
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Shalnov [3]

Answer:

\frac{1}{45}

Step-by-step explanation:

Substitute x = 2 into g(x) and evaluate

g(2) = \frac{1}{5} × (\frac{1}{3})²

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5 0
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6 0
3 years ago
Which statement about the figure MUST be true? Select all that apply.
olga55 [171]
<h2>○=> <u>Correct options</u> :</h2><h2>□\color{plum}\tt\bold{(C) \: SR = 27}</h2><h2>□\color{plum}\tt\bold{(D) \: QR = 54 }</h2><h3><u>Steps to derive the correct options</u> :</h3>

Since two sides and one included angle is equal in △PQS and △PRS, we can conclude that they are congruent under the SAS congruence criterion.

Which means :

▪︎Angle S = Angle S

▪︎PS = PS

▪︎QS = RS

Given :

Measure of segment QS = 6n+3

Measure of segment RS = 4n+11

Thus :

= \tt6n + 3 = 4n + 11

= \tt6n + 3 - 4n = 11

=\tt 2n + 3 = 11

= \tt2n = 11 - 3

= \tt2n = 8

=\tt n =  \frac{8}{2}

\hookrightarrow\color{plum}\tt n = 4

Thus, the value of n = 4

Measure of segment QS :

=\tt 6n + 3

= \tt6 \times 4 + 3

= \tt24 + 3

\color{plum}\tt \: \bold{QS = 6n + 3 = \tt\bold{27}}

Thus, measure of QS = 27

Measure of RS :

=\tt 4n + 11

=\tt 4 × 4 + 11

=\tt 16+11

\color{plum}\tt \: \bold{RS = 4n + 11 = \tt\bold{27}}

Measure of QR :

=\tt 27+27

\color{plum}\tt \: \bold{QR = 27+27 \tt\bold{=54}}

Thus :

▪︎QS = 27

▪︎RS = 27

▪︎QR = 54

Therefore, the correct options are :

▪︎(C) SR = 27

▪︎(D) QR = 54

7 0
3 years ago
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kykrilka [37]

Answer:

No, they are not proportional. 3/5 with equal out to 15/25 by using the method of Least Common Denominator!

Step-by-step explanation:

Hope this helps :)

7 0
2 years ago
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