Q^2 - 125 = 0
q^2 = 125
q = +/- sqrt 125 = 11.18, -11.18
Answer:
Sorry I could only find the answer to the second part.
y=56x
Let's try the actual solution of the system
<span>y = –2x + 1
y = –2x – 3
Note that the slopes of the graphs of these two lines are the same: -2.
That means that the lines are parallel to one another.
Only the y-intercepts (1 and -3) are different.
Since the 2 lines never intersect, the system has no solution.
</span>
Answer:
B.
(3x + 4)(x − 7)
Step-by-step explanation:
If you multiply.
3x2-21x+4x-28
3X2-17x-28
Answer:
C = (A*P - 8.4Y -330T + 200I) / 100
Step-by-step explanation:
P = (8.4Y + 330T + 100C -200I ) / A
now we have to calculate completed passes C for given P, Y, T, I, A
A*P = 8.4Y + 330T -200I +100C
100C = A*P - 8.4Y - 330T + 200I
C = (A*P - 8.4Y -330T + 200I) / 100
I just solved the equation for C