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love history [14]
3 years ago
8

What is the sum of the solutions for 6x^2 − x − 2 = 0?

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

The sum is 1/6

Step-by-step explanation:

This factors into

Factors

(3x - 2)(2x + 1) = 0

<em><u>First root</u></em>

3x - 2 = 0

3x = 2

x = 2/3

===============

<em><u>Second Root</u></em>

2x + 1 = 0

2x = 1

2x = - 1

x = - 1/2

===============

The two roots are 2/3 and - 1/2

When you add these two together, you get

2/3 - 1/2 = 4/6 - 3/6 = 1/6

The two roots add up to 1/6


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Paladinen [302]
The slope of the first equation would be -5/2 because
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7
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Answer:

1/4=slope

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Step-by-step explanation:

the equation in slope intercept form would be y=1/4x-8

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Step-by-step explanation:

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Algebra Complete the table.Write the
AURORKA [14]

Step-by-step explanation:

<em>In the second column, we can see that every value of n is being added by 6. </em>

  • Thus, the expression is n + 6.

<em>Now, let's substitute the value of n in each column to verify each column. Then, using the expression, let's find the value of n + 6 where n = 28.</em>

<u>When n is 12:</u>

  • n + 6 = 18
  • 12 + 6 = 18
  • 18 = 18

<u>When n is 15:</u>

  • n + 6 = 21
  • 15 + 6 = 21
  • 21 = 21

<u>When n is 21:</u>

  • n + 6 = 27
  • 21 + 6 = 27
  • 27 = 27

<em>Thus, the expression is proven correct. Now, let's find n + 6 when n is 28.</em>

<u>Finding n + 6 when n is 28:</u>

  • n + 6 = x
  • 28 + 6 = x
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Thus, the missing value in the table is 34.

4 0
2 years ago
the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.
suter [353]

Answer:

The width of the photo is 4w^2+6w+4.

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

6w^2+8

The photo is covered by a frame border and the width of the border is

w^2-3w+2

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})

\text{Width of the photo}=6w^2+8-2(w^2-3w+2)

\text{Width of the photo}=6w^2+8-2w^2+6w-4

\text{Width of the photo}=4w^2+6w+4

Therefore the width of the photo is 4w^2+6w+4.

4 0
3 years ago
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