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Alika [10]
3 years ago
7

Find the distance between the points given. (-10, 3) and (-10, 12) 9 15

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0
The distance between the points (x₁,y₁) and (x₂,y₂):
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(-10,3) \\
x_1=-10 \\ y_1=3 \\ \\ (-10,12) \\ x_2=-10 \\ y_2=12 \\ \\
d=\sqrt{(-10+10)^2+(12-3)^2}=\sqrt{0+9^2}=\sqrt{9^2}=9

Another method:
The points have the same x-coordinate so they lie on the same line. y-coordinates are positive so you just subtract 3 from 12. See the picture in the attachment.

The answer is 9.

Rom4ik [11]3 years ago
8 0
The way to solve it can be shorter :) 
Just look, that  these points have got the same x-coordinate, 
so they lie  on the same line, which is parallel to the OY axis, 
So  your taks is only  find different  in y-coordinate. That is
12-3 = 9 
And this is answer :)
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(i) Note that it is given to you that 3a + 2b = 9

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~

5 0
3 years ago
Read 2 more answers
a storeroom 21 feet long, 15 feet wide, and 11 feet high was enlarged to a length of 25 feet and a width of 17 feet. how many cu
xenn [34]
<h2>1210 cubic feet</h2>

Step-by-step explanation:

       Initial dimensions of the storeroom were 21\text{ }ft length, 15\text{ }ft width and 11\text{ }ft height.

       The room is in the shape of a cuboid. Volume of a cuboid = V=l\times b\times h, where l,b,h are the length, width and height of the cuboid.

       So, Volume of storeroom initially = 21\text{ }ft\text{ }\times15\text{ }ft\text{ }\times11\text{ }ft\text{ }=3465\text{ }ft^{3}\text{ }

       Finally, the length was increased to 25\text{ }ft and width to 17\text{ }ft.

       Final volume of storeroom = 25\text{ }ft\text{ }\times 17\text{ }ft\text{ }\times 11\text{ }ft\text{ }=4675\text{ }ft^{3}\text{ }

       Increase in volume = 4675\text{ ft}^{3}-3465\text{ ft}^{3}=1210\text{ ft}^{3}

∴ 1210 cubic feet of storage was added.

7 0
3 years ago
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