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Elena L [17]
3 years ago
8

Help if good at math

Mathematics
2 answers:
tatyana61 [14]3 years ago
7 0

Hey!

Hope this helps....

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

For Question 2: 6+3+n=12

This is because we know that there is a combined total of 12, so it has to equal 12 (which cancels out C), we also know that the question is not saying anything that implys that we are multiply anything thing (which cancels out B, and D), so we are only left with A.) 6+3+n=12


For Question 4: 2 (Fraction 2 over 3)

This is because when we substitute all those choices in for y, we get...

2/(3*(3/8)) ~ 1.77778

2/(3*(5/12)) = 1.6

2/(3*(11/12)) ~ 0.727273

2/(3*(8/3)) = 0.25

^^^^ I got 8/3 from A (b/c) > ((A*c)+b)/c

(And we know 1/4 = 0.25)

Mariana [72]3 years ago
3 0
Question 2 would be 6+3+n=12

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Construct a polynomial function with the following properties: fifth degree, 4 is a zero of multiplicity 3, −4 is the only other
Nonamiya [84]

Answer:

Step-by-step explanation:

Hello,

degree 5

4 is a zero of multiplicity 3 -> (x-4)^3 is a factor

-4 is the only other zero, so the multiplicity is 5-3=2 -> (x+4)^2 is a factor

leading coefficient is 4 so we can write

\boxed{4(x-4)^3(x+4)^2}

If there is something that you do not understand or you are blocked somewhere let us know what / where.

Thank you.

8 0
3 years ago
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad  B
\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
Read 2 more answers
How do you tell if a number is irrational or rational?
Korvikt [17]
A rational number is any number that can be expressed as a fraction
(ex: -5/2, 4 1/7, and 8/13)

An irrational number is any number that cannot be expressed as a fraction; a non-repeating, non-terminating decimal (ex: pi, 0.121231234...)

Hope this helps! :)
6 0
3 years ago
Help i don't know what to do I will give brainiest
sukhopar [10]

Answer:

The sum will be whichever number has the greater value.

Step-by-step explanation:

Let's say you have (-2) + 4 = ?

The number with the greater value is 4.

So the sum of your answer would be a positive, since the greater number has a positive sign.

3 0
3 years ago
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timofeeve [1]

Answer:

25

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B = 500 + 50*M

Costing the same means equal, so we have the equation:

70M = 500 + 50M

-50M           -50M

 

20M = 500

20M / 20 = 500 / 20

m- 25 months

5 0
3 years ago
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