Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
<u>Point-slope form</u>: y - 12 = 10 (x - 5)
<u>Slope-Intercept form</u>: y= 10x - 38
Step-by-step explanation:
im not fully sure which equation ur looking for but i think thats right lol. hopefully this helps ! :)
Answer: Hexagon, and is it the perimeter for above or below? below is 60cm and above is 20cm
Step-by-step explanation: Hexagons have 6 sides, and for perimeter just add up all the sides together
Answer:
an=6+6(n-1)
Step-by-step explanation:
