Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
The correct answer is A....
Answer:
a. body cells
Explanation:
Body cells are eukaryotic. Eukaryotic cells replicate via mitosis.
<span>C.
has strong legs for running
</span>
Answer:the villi of the intestine
Explanation:like the cristae of the mitochondria which increase the surface area for the production of ATP,the villi of the intestine acts similarly.
In animals, digested food pass from the stomach to the intestine. In the intestine , enzymes acts on the food. Absorption of food takes place there and there are some structures that facilitates it. The walls of the intestine have numerous foldings , alongside the presence of finger like projection called villi. Microvilli are also presence from the cell walls of the intestine . These projections increase the surface area for the absorbing of food .they brush against food in the intestine and promotes absorption of nutrients.
