Answer:
7. is G
8. f(4)=-120
Step-by-step explanation:
7. les do f(0)=4 since its the easiest
F. f(0)=0.4(0+5)(0-2)
0.4*-2*5=-4 NOT IT. the ans. is +
G. f(0)=-0.4(0+5)(0-2)
-0.4*-2*5=4 YESSSSSS
H. f(0)=-0.4(0-5)(0+2)
-0.4*2*-5=4 YESSSSSS
J. f(0)=0.4(0-5)(0+2)
0.4*2*-5=-4 NOT ITTTT
so G n H
Put both equation=0
G. 0=-0.4(x+5)(x-2)
x=-5,2 YASSSS this is the ans.
Answer:
Area = 1/2 Base x height
Step-by-step explanation:
To find the area of a triangle, multiply the base of the height and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into two triangles.
My best guess is that 73 cartons are needed. Here's how:
876/12 ( because the jugs are shipped in cartons containing 12) = 73
This is just a guess, I'm sorry if someone proves me wrong, but this is what I have.
The complete question in the attached figure
we know that
m angle bad =75°
remember that on parallelogram
(∠A + ∠<span>B) = 180°
[Since, sum of the interior angles on the same side of the transversal is 180°]
therefore
</span>∠B=180°-∠A=180°-75°=105°
∠B=105°
<span>Similarly
∠B + ∠C = 180°
∠C + ∠D = 180°
and ∠D + ∠A = 180°</span>
<span>Thus, the sum of any two adjacent angles of a parallelogram is 180°.
</span>
m angle bcd=∠C=180-∠B=180°-105°=75°
the answer is m angle bcd=75°
Answer:
a) 0.1829
b) 0.6823
c) 0.0413
Step-by-step explanation:
We are given the following information:
We treat adult having little confidence in the newspaper as a success.
P(Adult have little confidence) = 62% = 0.62
Then the number of adults follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
a) exactly 5
0.1829 is the probability that exactly 5 out of 10 U.S.adults have very little confidence in newspapers.
b) atleast six
0.6823 is the probability that atleast 6 out of 10 U.S. adults have very little confidence in newspapers.
c) less than four
0.0413 is the probability that less than 4 out of 10 U.S. adults have very little confidence in newspapers.