Answer:
The total applied force on the trolley is 5 N toward the North.
Explanation:
In this problem, Ben is pushing the trolley to north and Gary is pushing it to south. So both the forces are acting 180° opposite to each other. As force is a vector quantity, the net force or total force acting on any object should be calculated by vector addition of number of forces along with their directions. So in this case, if we consider the force Ben is applying as F1 and the force Gary is applying as F2 on the trolley. Then the net or total force acting on the trolley will be 
. This is because, F1 and F2 are acting opposite to each other in direction.Thus, 
.
So the total force acting on the trolley is 5 N and it is toward the north direction.
Answer:
V₂ = 18.13 L
Explanation:
Given data:
Mole of gas = 1 mol
Initial temperature = 273 K
Initial pressure = 1 atm
Final volume = ?
Final temperature = -41°C (-41+273 = 232 K)
Final pressure = 805 mmHg (805/760 = 1.05 atm)
Solution:
First of all we will calculate the initial volume of gas.
PV = nRT
V = nRT/P
V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm
V = 22.4 L/atm / 1 atm
V = 22.4 L ( initial volume)
Now we will determine the final volume by using equation,
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 22.4 L × 232 K / 273 K × 1.05 atm
V₂ = 5196.8 atm .L. K / 286.65 atm.K
V₂ = 18.13 L
Answer is: thermal conductuction.
Thermal conductuction is the transfer of heat<span> through physical contact. </span>Thermal conduction<span> is the transfer of heat</span> by microscopic collisions of particles. <span>Heat spontaneously flows from a hotter to a colder body.
</span>The process of heat conduction depends on four basic factors: the temperature gradient<span>, the cross section of the </span>materials<span> involved, their path length and the properties of those materials.</span>
Answer: A. Object Q refracts red light, and object R diffracts red light.
Explanation:
