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4 years ago

What is a result of the unequal electron sharing in a water molecule?

Chemistry

1 answer:

Katarina [22]4 years ago

4 0

Answer:

The right choice is c. Water molecules have a weakly positive hydrogen end.

Explanation:

The unequal sharing of electrons in water molecule gives a slight negative charge near its oxygen atom ( see image below) and a slight positive charge near its hydrogen atoms. A neutral molecule that has a partial positive charge at one end and a partial negative charge at the other, it is a polar molecule.

a. Water molecules have a nonpolar bond.

It is wrong choice because water has polar bond .

b. Water molecules have a weakly positive oxygen end.

Also, a wrong choice due to water molecule gives a slight negative charge near its oxygen atom.

c. Water molecules have a weakly positive hydrogen end.

This is the right choice.

d. Water molecules have two oxygen and two hydrogen atoms

It is wrong choice because water has one oxygen and two hydrogen atoms

So, the right choice is

c. Water molecules have a weakly positive hydrogen end.

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Answer in the correct significant figures: 9.66 / 0.33

insens350 [35]

9.66/0.33
2 sig figs
=29

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3 years ago

Cheng made a chart to categorize resources. Which correctly completes the chart? X: Geothermal energy Y: Nonrenewable X: Wind Y:

madam [21]

X: Geothermal energy
Y: Nonrenewable

So the answer is A

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3 years ago

Read 2 more answers

SO2 + 2NaOH → Na2SO3 + H2O

katen-ka-za [31]

Answer:

There will be produced 157.55 grams of Na2SO3. The limiting reactant is NaOH. SO2 is in excess, there will remain 19.9 grams of SO2.

Explanation:

Step 1: Data given

Mass of SO2 = 100 grams

Mass of NaOH = 100 grams

Molar mass of SO2 = 64.07 g/mol

Molar mass of NaOH = 40 g/mol

Molar mass of Na2SO3 = 126.04 g/mol

Step 2: The balanced equation

SO2 + 2NaOH → Na2SO3 + H2O

Step 3: Calculate moles SO2

Moles SO2 = mass SO2 / molar mass SO2

Moles SO2 = 100.0 grams / 64.07 g/mol

Moles SO2 = 1.561 grams

Step 4: Calculate moles of NaOH

Moles NaOH = 100.0 grams / 40 g/mol

Moles NaOH = 2.5 moles

Step 5: Calculate limiting reactant

For 1 mol of SO2 we need 2 moles of NaOH to produce 1 mol Na2SO3 and 1 mol of H2O

NaOH is the limiting reactant. It will completely be consumed.(2.5 moles).

SO2 is in excess. There will be consumed 2.5 / 2 = 1.25 moles of SO2

There will remain 1.561 - 1.25 = 0.311 moles of SO2. This is 0.311 * 64.07 g/mol = 19.9 grams

Step 6: Calculate moles of Na2SO3

There will be produced 1.25 moles of Na2SO3

Step 7: Calculate mass of Na2SO3

Mass Na2SO3 = 1.25 * 126.04 g/mol

Mass Na2SO3 = 157.55 grams

There will be produced 157.55 grams of Na2SO3. The limiting reactant is NaOH. SO2 is in excess, there will remain 19.9 grams of SO2.

6 0

4 years ago

Which of the following molecules is the primary product of photosystem I?a) Carbon dioxideb) Oxygenc) NADPHd) ATP

Lina20 [59]

Answer:

The primary product of the photosystem I is NADPH.

Explanation:

NADPH is the acronym of Nicotinamide adenine Dinucleotide Phosphate. This NADPH plays a vital role in many chemical reactions that take place during photosynthesis process. NADPH is released as a product in Photosystem I.

In the photosystem I process, the molecule present will absorb sunlight energy and transfers it to electrons to produce NADPH. This NADPH molecule is used as fuel for the chemical process that occurs during the 2nd stage of the photosynthesis process. Its molecular formula is $C_{12} H_{30} N_{7} O_{17} P_{13}$ . It acts as a fundamental metabolite.

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3 years ago

Do all collisions lead to a reaction?

4vir4ik [10]

No, not every collision makes a reaction.

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4 years ago