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2 years ago

13

The rhythmic use of spoken or semi-sung lyrics is called:

1 answer:

Sholpan [36]2 years ago

3 0

C. Rapping, is your answer.

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What is the volume of 0.5 M solution of NaOH that contains 3.6 mol of solute?

nasty-shy [4]

Answer:

The volume of NaOH solution is 0.532 L.

Step 1. Calculate the moles of NaOH.

Moles = 11.5 g NaOH * (1 mol NaOH/40.00 g NaOH) = 0.2875 mol NaOH

Step 2. Calculate the volume of NaOH

Volume = 0.2875 mol NaOH * (1 L NaOH/0.540 mol NaOH) = 0.532 L

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2 years ago

Chemistry help!

Norma-Jean [14]

Refer to the attachment.

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2 years ago

In a crystal lattice of an ionic compound,

Lena [83]

Answer:

i would try B

Explanation:

6 0

3 years ago

Calculate the molarity of a solution that contains 0.175 mol of zncl2 n exactly 150 ml of solution.

scoray [572]

Molarity = mol/L

0.175 mol
0.15 L (1000 mL = 1 L)

Molarity = 0.175 mol/0.15 L = 1.1666667 M

3 0

2 years ago

Read 2 more answers

Natural gas is almost entirely methane. A container with a volume of 2.65L holds 0.120mol of methane. What will the volume be if

mrs_skeptik [129]

The final volume of the methane gas in the container is 6.67 L.

The given parameters;

<em>initial volume of gas in the container, V₁ = 2.65 L</em>
<em>initial number of moles of gas, n₁ = 0.12 mol</em>
<em>additional concentration, n = 0.182 mol</em>

The total number of moles of gas in the container is calculated as follows;

$n_t = 0.12 + 0.182 = 0.302 \ mol$

The final volume of gas in the container is calculated as follows;

$PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1 n_2}{n_1} \\\\V_2 = \frac{2.65 \times 0.302}{0.12} \\\\V_2 = 6.67 \ L$

Thus, the final volume of the methane gas in the container is 6.67 L.

Learn more here:brainly.com/question/21912477

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2 years ago