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butalik [34]
3 years ago
14

Determine which equations have the same solution set as – x + = 6x by recognizing properties, rather than solving. Check all tha

t apply. 4 – 6x + 1 = 36x – x = 6x 4 – x + 1 = 6x + x = 6x 5 = 30x 5 = 42x
Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0

Answer:

1, 2, and 6

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
7 0

Answer:

1 2 6

Step-by-step explanation:

You might be interested in
13 = m/4 + 7 can you show work too
lukranit [14]

The correct value of this equation is <u>m = </u><u>24</u>

<h3>Resolution method</h3>

This equation contains a fractional term. We note that the denominator of this equation is the <u>term 4</u>. Therefore, we will multiply the sides by <u>4</u>:

13 = m/4 + 7

13 . 4 = 4(m/4) + 7 . 4

52 = m + 28

Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

52 = m + 28

-m = 28 - 58

-m = -24

<u>m = 24</u>

Therefore, the correct value of this equation will be <u>m = 24</u>

7 0
2 years ago
Please help me solve this
sleet_krkn [62]

Answer:

24

Step-by-step explanation:

4x + 6 = 102

-6. -6

4x= 96

x=24

6 0
3 years ago
Read 2 more answers
Let f(x) be a quartic polynomial with integer coefficients and four integer roots. Suppose the constant term of f(x) is 6.(a) Is
frez [133]

Answer:

  (a) yes

  (b) no; see below

Step-by-step explanation:

(a) Integer roots of the quartic will be integer divisors of 6. One of the divisors of 6 is 3, so 3 is a possible root.

(b) In order for 3 to be a double root, it would have to be a double factor of 6. The only integer factors of 6 are 1, 2, 3, 6. (3² = 9 is not one.)

___

The quartic can be written as ...

  k(x -a)(x -b)(x -c)(x -d) . . . . . where a, b, c, d, k are integers

The constant term will be kabcd, of which each of the roots is a factor. If the constant is 6 and one root is d=3, then we must have

  kabcd = 3kabc = 6

  kabc = 6/3 = 2

Among these four integer factors, there must be an even number of minus signs, and one that has the value ±2. Another root whose value is 3 will not satisfy the requirements.

3 0
3 years ago
Can someone help me on this
Sidana [21]

Answer:

Area = 702.9 or 703

Step-by-step explanation:

By Pythagoras the. first, we need to find the base!

(H)2 = (P)2 + (B)2

(82)2 = (18)2 + b2

6724 = 324 + b2

b2 = 6724-324

b2 = 6100

b = √6100

b = 78.1

note - they all are in square

Now, area of the triangle:-

1/2 * b * h

1/2 * 78.1 * 18

= 702.9

Hope it helps!

6 0
3 years ago
Read 2 more answers
HURRY, DUE IN 11 MINUTES!! WILL MARK BRAINLIEST!!
Setler [38]

Answer:

The answer is: (1, -10)

5 0
3 years ago
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