It's the arithmetic sequence not geometric sequence.
Answer:
Step-by-step explanation:
5(x+7) + 2(y-1)
here x=7 and y=2
so 5(7+7)+2(2-1)= 5*14+ 2*1
70+2=72
1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer:
A.
Step-by-step explanation:
R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32