What is true about mass and volume of all sinking objects

A submarine can detect an approaching enemy submarine using sonar. If a stationary submerged submarine emits a 100kHz tone and r

prisoha [69]

Answer:

B ) 1.5 m/s

Explanation:

For the apparent frequency reflected by enemy submarine , the Doppler effect formula is

F = F₀ ( V + v) / (V - v)

F anf F₀ are real and apparent frequency , V and v are velocity of sound and velocity of enemy submarine respectively.

ΔF / F₀ = $\frac{2\times v}{V -v}$

Put ΔF = 200; F₀ = 100000 and V = 1482

200 / 100000 = $\frac{2\times v }{1482-v}$

v = 1.5 m s⁻¹ .

8 0

4 years ago

A book has a mass of 5 lb what is the mass of the book kg

OverLord2011 [107]

The mass of the Book is 2.27 kg.

6 0

3 years ago

You are given two converging lenses to build a compound microscope. Lens A has focal length 0.50 cm and lens B has focal length

siniylev [52]

Answer:

The lens to be used for the objective is lens A

Explanation:

The objective of a compound microscope

The focal length of the lens used for the objective = 1/(magnification obtained)

The focal length of most modern is equal to the tube length

The range of sizes for the focal length of a microscope is between 2 mm and 40 mm

Therefore, the appropriate lens to be used for the objective of the compound is lens A that has a focal length of 0.50 cm = 5 mm

6 0

3 years ago

1. In which direction can a force be exerted on an object?

My name is Ann [436]

A. Any Direction
This should be obvious, as you can push down on something, push it to the sides, and push something up. Hope this helped!

3 0

4 years ago

A block attached to a spring with an unknown spring constant oscillates with a period of 2.0 s. What is the period if

Zigmanuir [339]

Answer:

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

Explanation:

The statement is incomplete. We proceed to present the complete statement: A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if a. The mass is doubled? b. The mass is halved? c. The amplitude is doubled? d. The spring constant is doubled?

We have a block-spring system, whose angular frequency ( $\omega$ ) is defined by the following formula:

$\omega = \sqrt{\frac{k}{m} }$ (1)

Where:

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass, measured in kilograms.

And the period ( $T$ ), measured in seconds, is determined by the following expression:

$T = \frac{2\pi}{\omega}$ (2)

By applying (1) in (2), we get the following formula:

$T = 2\pi\cdot \sqrt{\frac{m}{k} }$

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

8 0

3 years ago