A submarine can detect an approaching enemy submarine using sonar. If a stationary submerged submarine emits a 100kHz tone and r
1 answer:
Answer:
B ) 1.5 m/s
Explanation:
For the apparent frequency reflected by enemy submarine , the Doppler effect formula is
F = F₀ ( V + v) / (V - v)
F anf F₀ are real and apparent frequency , V and v are velocity of sound and velocity of enemy submarine respectively.
ΔF / F₀ =
Put ΔF = 200; F₀ = 100000 and V = 1482
200 / 100000 =
v = 1.5 m s⁻¹ .
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Answer:
1450.4 KN
Explanation:
Pressure = ρhg
where: ρ is the density of the liquid, h is the height and g the force of gravity.
Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury
So that,
i. Pressure of oil = ρhg
(ρ = 0.8 g/cm³ = 800 kg/m³)
= 800 x 5 x 9.8
= 39200
Pressure of oil = 39200 N
ii. Pressure of water = ρhg
(ρ = 1 g/cm³ = 1000 kg/m³)
= 1000 x 8 x 9.8
= 78400
Pressure of water = 78400 N
ii. Pressure of mercury = ρhg
(ρ = 13.6 g/cm³ = 13600 kg/m³)
= 13600 x 10 x 9.8
= 1332800
Pressure of mercury = 1332800 N
So that,
Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800
= 1450400
= 1450.4 KN
Total pressure exerted by the liquids at the base is 1450.4 KN.
Answer:0.210 ft/min
Explanation:
Given
Length of trough
width of base
height of triangle
From Similar triangles property
volume of water in time t
differentiating
at
