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KonstantinChe [14]
3 years ago
11

Where do electrons spend most of their time?

Physics
2 answers:
AVprozaik [17]3 years ago
8 0

Answer:

Before bonding, the atom's electrons spend most of their time around the nuclei of each atom.

Explanation:

Once bonded, the electrons spend most of their time between the two nuclei.

GrogVix [38]3 years ago
5 0

Answer:

around the nuclei of each atom

Explanation:

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A chemical plant produces ammonia using the following reaction. What
puteri [66]
The correct answer is A
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3 years ago
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A teenager of mass m1 = 72 kg pushes backward against the ground with his foot as he rides his skateboard. This exerts a horizon
Ray Of Light [21]

Answer:

The acceleration of the skateboard is -9.65 m/s².

Explanation:

Given that,

Mass of teenager = 72 kg

Force F_{foot}=11\ N

Mass of skateboard = 2.8 kg

Suppose, the determine the numerical value for the magnitude of the acceleration of skateboard

We need to calculate the acceleration of skateboard

Using balance equation

F-(m_{1}+m_{2})g=(m_{1}+m_{2})a

Put the value into the formula

11-(72+2.8)\times9.8=(72+2.8)\times a

a=\dfrac{11-(72+2.8)\times9.8}{(72+2.8)}

a=-9.65\ m/s^2

Hence, The acceleration of the skateboard is -9.65 m/s².

5 0
3 years ago
Which of the following is TRUE regarding photoelectric effect from the experimental data?
Maksim231197 [3]

Answer:

Experiments showed that increasing the light frequency increased the kinetic energy of the photoelectrons, and increasing the light amplitude increased the current.

Explanation:

The photocurrent increases linearly with the intensity of the incident light but is independent of its frequency. The stopping potential increases linearly with the frequency of the incident light but is independent of its intensity.

6 0
3 years ago
A 60.0 kg object is moving east at 8.00 m/s, and then slows down to 4.00 m/s. How much work was done?
Artist 52 [7]
The answer is  -1440. That is letter A.
8 0
3 years ago
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Assume a beam with stirrups inclined at 60o angle with respect to the longitudinal steel resisting cracks developing at 45o angl
arlik [135]

Answer:

Shear resistance of a inclined stirrup is given by  

 Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

Explanation:

The shear resistance is checked in accordance with BS8110: Part 1, section 3.5.5. Shear resistance of a inclined stirrup is given by  

 Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

where,

 Vᵇ=design shear resistance of inclined bars

Asb=cros-sectional area of the inclined bars

Fy=characteristics strength of the stirrups

α=angle between the inclined bars and the axis of the beam

β=angle between the compression strut of inclined bars and the axis of the beam

sᵇ=spacing of the inclined bars

d= effective depth   and d'=effective depth minus cover to reinforcement

The shear stress is given by    

v=V/bd  

 where V is the shear force due to ultimate loads. If v is shear stress

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3 years ago
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